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2 years ago

2.

Mathematics

1 answer:

garri49 [273]2 years ago

8 0

Answer:

43.75 mi/h
131.25 mi

Step-by-step explanation:

(a) 70 km/h · (1 mi/h)/(1.6 km/h) = 70/1.6 mi/h = 43.75 mi/h

(b) In 3 hours, the car will travel ...

(43.75 mi/h)(3 h) = (43.75)(3) mi = 131.25 mi

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PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab

Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

The product of slopes of two perpendicular lines is -1.

Slope of GR is

$\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}$

Slope of RT is

$\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1$

Product of slopes of GR and RT is

$\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1$

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

$(x,y)\rightarrow(x-1,y-2)$

Then the coordinates of T' are

$(2,6)\rightarrow(2-1,6-2)$

$(2,6)\rightarrow(1,4)$

Slope of RT' is

$\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}$

Product of slopes of GR and RT' is

$\frac{-4}{3}\times \frac{3}{4}=-1$

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

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2 years ago

How to solve the equation for the indicated variable: a-6[b-3(c-x)], for x.

Brilliant_brown [7]

6b-18c+18x is simplified for you

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2 years ago

What is the equation for the line of reflection a. x= 3 b. y = 3 c. y = x d. x = 6

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Answer:

The answer to that question is c. y = x

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2 years ago

PLS HELP ME WITH THIS ALGEBRA!

artcher [175]

Answer:

120 g

Step-by-step explanation:

A salt solution contains 10% salt and weights 80g.

Salt content of the solution is:

80*0.1 = 8 g

4% solution has 8 g salt, total solution is:

0.04x = 8
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6 0

2 years ago

How would you draw a counterexample to this?

NeX [460]

Melanie said:
Every angle bisector in a triangle bisects the opposite side perpendicularly.

A 'counterexample' would show an angle bisector in a triangle that DOESN'T
bisect the opposite side perpendicularly.

See my attached drawing of a counterexample.

Both of the triangles that Melanie examined have equal sides on both sides
of the angle bisector. That's the only way that the angle bisector can bisect
the opposite side perpendicularly. Melanie didn't examine enough different
triangles.

6 0

3 years ago