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puteri [66]
3 years ago
13

Solve (2a^x + 1/2b^x)^2

Mathematics
1 answer:
alexira [117]3 years ago
6 0

Answer:

(4a^{2x} )+2a^{x} b^{x} + \frac{b^{2x} }{4}

Step-by-step explanation:

The given equation is

(2a^x + \frac{1}{2}b^{x} } )^2 ...........(i)

we know the formula i.e.

(a+b)^{2}= a^{2}+ b^{2} +2(a)(b)

Applying this formula on equation (i) gives

= (2a^{x} )^{2} +(\frac{1}{2})^{2}*(b^{x} )^{2} + 2 (2a^{x} )(\frac{1}{2} b^{x})

Opening the sqaure gives and canceling  \frac{1}{2} with 2 gives us

= 4a^{2x} + \frac{1}{4}b^{2x} + 2a^{x}b^{x}

= (4a^{2x} )+2a^{x} b^{x} + \frac{b^{2x} }{4}

which is the answer

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