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Andrej [43]
3 years ago
14

Solve the quadratic equation by completing the square. x2 + 6x - 5 = 0

Mathematics
2 answers:
Daniel [21]3 years ago
7 0
X= 5/8 or in decimal form it is x= 0.625
Fudgin [204]3 years ago
5 0

Answer:

C) x = -3 ± sqrt(14)

Step-by-step explanation:

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Is this an arithmetic sequence 1,1/2,1/4,1/8
valentinak56 [21]

Answer:

No, it is a geometric sequence.

Step-by-step explanation:

The 2nd term is half the first term, the 3rd term is half the second term, etc..

If it were an arithmetic sequence you would need to add or subtract the same difference each term, but here you are multiplying each term by 1/2.

4 0
3 years ago
The first term and the common ratio of a G.P are respectively 3 and 1/2.write down the first five terms​
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

a =3 ;r  = 1/2

first term = 3

second term = 3*1/2 = 3/2

third term = 3/2 * 1/2 = 3/4

Fourth term = 3/4*1/2 = 3/8

Fifth term = 3/8 * 1/2 = 3/16

GP is: 3,3/2,3/4,3/8,3/16......

8 0
4 years ago
Find the slope of the line?<br>A1/3<br>B-1/3<br>C3<br>D-3
nirvana33 [79]
The answer is 1/3.
Rise\run = 2/6 and then u simplify
3 0
3 years ago
Read 2 more answers
Please help its7to10 I be waiting like two hours
Bingel [31]

Answer:

Please check the explanation!

Step-by-step explanation:

Important factors to remember regarding the like terms:

  • 'Like terms' are terms whose variables such as 2x and 6x are the same.
  • Also if the variables contain the exponents such as 4 in x⁴, they must be the same too.
  • Since the coefficient doesn't affect likeness, therefore we can say that all constant terms would be treated as the like terms.

Question 7

Given the terms

2b     b⁶     b     x⁴     3b⁶     2x²

From the list of terms, there are two groups of like terms which are:

2b     b       (Like terms containing the variable b)

b⁶      3b⁶    (Like terms containing the variable b with the same exponents)

  • The remaining two x⁴  and 2x² terms are different from each other and the rest of the terms

Question 8

Given the terms

6     2n     3n²     3m²     n/4     7

From the list of terms, there is one group of like terms which are:

6     7       (Constants Like terms)

2n    n/4   (The terms with the same variable n)

  • All the remaining terms such as 3n², 3m² are all different from each other and the rest of the terms.

Question 9

Given the terms

10k²      m     3³     p/6     2m

From the list of terms, there are there is one group of like terms which are:

m     2m     (The terms withe same variable m)

  • All the remaining terms such as 10k², 3³, p/6  are all different from each other and the rest of the terms.

Question 10

Given the terms

6³      y³     3y²     6²     y      5y³

From the list of terms, there are two groups of like terms which are:

y³    5y³     (The terms withe same variable m and exponent)

6³     6²      (Constant like terms. Plz don't confuse the power as all are the same constant terms)

  • All the remaining terms such as y and 3y² are all different from each other and the rest of the terms.

6 0
3 years ago
a model car has a scale of 3cm : 2m. The length of the actual hood of the car is 1 m. what is the length of the hood of the mode
kherson [118]

Set up a proportion:

3cm/2m = x/1m

Cross-multiply:

2x=3

Divide by 2:

x=1.5 cm

Hope this helps!

6 0
3 years ago
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