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2 years ago

11

10 computer operators can compose 120 pages in 2 hours. How many operators should work, if the same job is to be completed in 30

minutes?

1 answer:

cupoosta [38]2 years ago

6 0

Answer:

40 Operators

Step-by-step explanation:

if 10 operators worked on 120 pages for 2 hours

P operators will work on the same pages for 30min

note: 2hrs= 120min

10×120min/120= P × 30/120

cross multiply
make P subject of the formula

P= 10×120×120/120×30

P = 40 operators

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NEED HELP ASAP!!! Susan makes $5 per hour babysitting and $7 per hour as a life guard. Her goal is to make at least $140. which

Alchen [17]

Number of hours Babysitting: x
Number of horus Lifeguard: y

<span>Susan makes $5 per hour babysitting
</span>Money she makes Babysitting: 5x

Susan makes $7 per hour as a life guard
Money she makes as a life guard: 7y

Total money she mahes: 5x+7y

<span>Her goal is to make at least $140:
5x+7y>=140

Answer: First option
5x+7y>=140</span>

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2 years ago

What is the equation for the line?

Dima020 [189]

Answer:

y=8x

Step-by-step explanation:

y=mx+b

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2 years ago

Read 2 more answers

Stels [109]

Answer:

The maximum speed of Hal's airplane in still air is:

$v= 250\ miles/h$

The speed of the wind

$c = 50\ miles/h$

Step-by-step explanation:

Remember that the velocity v equals the distance d between time t.

$v=\frac{d}{t}$ and $t*v=d$

The distance that Hal travels when traveling with the wind is:

$(2\ hours)(v + c) = 600$ miles

Where v is the speed of Hal and c is the wind speed.

The distance when traveling against the wind is:

$(3\ hours)(v-c) = 600$ miles

Now we solve the first equation for v

$(2)(v + c) = 600$

$2v + 2c = 600$

$2v= 600-2c$

$v= 300-c$

Now we substitute the value of v in the second equation and solve for c

$3((300-c)-c) = 600$

$3(300-2c) = 600$

$900-6c = 600$

$-6c = 600-900$

$-6c = -300$

$6c = 300$

$c = 50\ miles/h$

Then:

$v= 300-(50)$

$v= 250\ miles/h$

The maximum speed of Hal's airplane in still air is:

$v= 250\ miles/h$

The speed of the wind

$c = 50\ miles/h$

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3 years ago

Solve the equation 186+10x=25.5x to find how many diving lessons <br><br><br> __ lesson(s)

vredina [299]

Answer: x=12

Steps shown in image below:

3 0

2 years ago

The coordinates of quadrilateral PQRS are P(–3, 0), Q(0, 4), R(4, 1), and S(1, –3). What best describes the quadrilateral?

denis-greek [22]

Answer:

Square

Step-by-step explanation:

Plot the vertices of the quadrilateral PQRS on the coordinate plane (see attached diagram). The diagram shows that this is a square. Let's prove it.

1. Find all sides lengths:

$PQ=\sqrt{(-3-0)^2+(0-4)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5\\ \\QR=\sqrt{(0-4)^2+(4-1)^2}=\sqrt{(-4)^2+(3)^2}=\sqrt{16+9}=\sqrt{25}=5\\ \\RS=\sqrt{(4-1)^2+(1-(-3))^2}=\sqrt{(3)^2+(4)^2}=\sqrt{9+16}=\sqrt{25}=5\\ \\SP=\sqrt{(1-(-3))^2+(-3-0)^2}=\sqrt{(4)^2+(-3)^2}=\sqrt{16+9}=\sqrt{25}=5$

All sides have the same lengths.

2. Find the slopes of all lines:

$PQ:\ \dfrac{4-0}{0-(-3)}=\dfrac{4}{3}\\ \\QR:\ \dfrac{1-4}{4-0}=-\dfrac{3}{4}\\ \\RS:\ \dfrac{-3-1}{1-4}=\dfrac{4}{3}\\ \\SP:\ \dfrac{0-(-3)}{-3-1}=-\dfrac{3}{4}$

Since the slopes of PQ and RS are the same, lines PQ and RS are parallel. Since the slopes of QR and SP are the same, lines QR and SP are parallel.

The slopes $\frac{4}{3}$ and $-\frac{3}{4}$ have the product of

$-\dfrac{3}{4}\cdot \dfrac{4}{3}=-1,$

then lines are pairwise perpendicular.

This means PQRS is a square.

4 0

3 years ago