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Cerrena [4.2K]
3 years ago
14

mike music sold 287 's on the first day of a 2day sale ,The store sold 96 more CD on The second day than on the first day ?How m

any CD in all were sold during the 2 day sale
Mathematics
1 answer:
mylen [45]3 years ago
4 0

287+96=the answer

good luck

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Events a and b are mutually exclusive. p(a) = 0.4 and p(b) = 0.5. what is p(a/b)?
Salsk061 [2.6K]
To figure this out, replace the variables with their given values.

p(a/b) = p(.4/.5)

Then you divide!

.4/.5 = .8

Hope this helps!
8 0
3 years ago
After dis if you get the answer right you get 50 points
svetoff [14.1K]

Answer:

5

Step-by-step explanation:

First you have 24-(5+9)/2

So do 5+9=14

24-14=10

10/2=5

answer is 5

7 0
2 years ago
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This . 9th and 10 pleasee solve thesee ?
kykrilka [37]
9 is 9600 cause if you divide 48 by 5 you get 9.6 then times 9.6 times 1000 you get 9600
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5 0
3 years ago
There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro
elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that \mu = 20.1, \sigma = 5.1.

You scored 24 on Exam A. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 20.1}{5.1}

Z = 0.76

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that \mu = 1031, \sigma = 215.

You scored 1167 on Exam B, s:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1167 - 1031}{215}

Z = 0.632

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

3 0
3 years ago
Hey can anyone help me on number B please?
NNADVOKAT [17]

Answer:60

Step-by-step explanation:all sides of the triangle have to be 180 degrees

5 0
3 years ago
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