(2k² + 5k - 6)(3k - 1)
(6k³ - 2k² + 15k² - 5k - 18k + 6)
6k² + 13k² - 23k + 6
Use the FOIL method to simplify the problem.
(FOIL stands for first outer, inner, last)
Since the buses travel in opposite directions, the speed at which they distance themselves is the sum of their speeds.
One bus travels at speed s.
The other bus travels at speed s + 15.
The sum of the speeds is s + s + 15 = 2s + 15
speed = distance/time
distance = speed * time
366 = (2s + 15) * 2
183 = 2s + 15
168 = 2s
s = 84
The slower bus travels at 84 km/h.
s + 15 = 84 + 15 = 99
The faster bus travels at 99 km/h.
Check:
In 2 hours, the slower bus travels 2 * 84 km = 168 km
In 2 hours, the faster bus travels 2 * 99 km = 198 km
In 2 hours, the buses are 198 km + 168 km = 366 km apart.
Our answer is correct.
Answer:
1.) D
2.) B
3.)
a.) 7x-34
b.) x (division symbol) 45 + 6
4.)
a.) x decreased by 216
b.) the quotient of 15 and x
Answer:
x = 1; y = 6
x = 5; y = 26
x = 8; y = 41
x = 10; y = 51
Step-by-step explanation:
Just substitute the x values
