Question

X=-9;y=4;z=8 -7z - 8y +5z

Answer 1

Answer:

Question

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Solve the following equations:

9x+y−8z=0,

4x−8y+7z=0,

yz+zx+xy=47.

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Solution

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Correct option is

A

x=±3;y=±5;z=±4

Let 9x+y−8z=0 .......(i)

4x−8y+7z=0 .......(ii)

yz+zx+xy=47 .......(iii)

Solving (i) and (ii) by cross multiplication

7−64

x

=

−32−63

y

=

−72−4

z

=k

⇒

−57

x

=

−95

y

=

−76

z

=k

⇒x=−57k,y=−95k,z=−76k .........(iv)

Substituting x,y and z in (iii), we get

(−95k)(−76k)+(−76k)(−57k)+(−57k)(−95k)=47

⇒16967k

2

=47

⇒k

2

=

16967

47

=

361

1

⇒k=±

19

1

Substituting k in (iv), we get

⇒x=±3,y=±5,z=±4

which is the required solution.

Step-by-step explanation:

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