Answer:
Question
Bookmark
Solve the following equations:
9x+y−8z=0,
4x−8y+7z=0,
yz+zx+xy=47.
Easy
Solution
verified
Verified by Toppr
Correct option is
A
x=±3;y=±5;z=±4
Let 9x+y−8z=0 .......(i)
4x−8y+7z=0 .......(ii)
yz+zx+xy=47 .......(iii)
Solving (i) and (ii) by cross multiplication
7−64
x
=
−32−63
y
=
−72−4
z
=k
⇒
−57
x
=
−95
y
=
−76
z
=k
⇒x=−57k,y=−95k,z=−76k .........(iv)
Substituting x,y and z in (iii), we get
(−95k)(−76k)+(−76k)(−57k)+(−57k)(−95k)=47
⇒16967k
2
=47
⇒k
2
=
16967
47
=
361
1
⇒k=±
19
1
Substituting k in (iv), we get
⇒x=±3,y=±5,z=±4
which is the required solution.
Step-by-step explanation:
here is your answer Hope you will enjoy and mark me as brainlist
thank you
