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mario62 [17]
3 years ago
9

Someone please help me as fast as possible just ignore the graph thing

Mathematics
1 answer:
fenix001 [56]3 years ago
8 0

14 \div 50 = x \div 7500
Cross multiply
50x = 105000
x = 2100

2100 trout.
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Find the area of the figure. Use 3.14 for π.
siniylev [52]

Answer:

Area of the figure= 51.5feet^2

Step-by-step explanation:

Area of the figure=Area of the middle rectangle+ Area the the two triangles

Area of the rectangle=Length*Width

Length= 8+3 =11 feet\\\\Width=4 feet

Area = 11*4\\\\      =44 feet^2

Area of the triangle with the height of 2 feet and base= 3 feet

Area= \frac{1}{2} *Base*Height

==\frac{1}{2} *3*2\\\\=\frac{1}{2}*6\\\\ =3 feet^2

Area of the triangle with the Height=3 feet and Base= 3 feet

Area= \frac{1}{2} *Base*Height

=\frac{1}{2}*3*3\\\\ =\frac{1}{2}*9\\\\ =4.5feet^2

Total Area of the figure=44+3+4.5=51.5 feet^2

5 0
3 years ago
Read 2 more answers
A (0, 2) and B (6,6) are points on the straight line ABCD.
elena-14-01-66 [18.8K]

Answer:

(18, 14)

Step-by-step explanation:

We know that C and D lie on the line AB and BC = CD = AB. Then we need to use the distance formula and equation of the line AB to find the other two coordinates.

The distance formula states that the distance between two points (x_1,y_1) and (x_2,y_2), the distance is denoted by: \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}. Let's find the distance between A and B:

d = \sqrt{(6-0)^2+(6-2)^2}=\sqrt{6^2+4^2} =\sqrt{36+16} =\sqrt{52} =2\sqrt{13}

Now say the coordinates of D are (a, b). Then the distance between D and B will be twice of 2√13, which is 4√13:

4√13 = \sqrt{(6-a)^2+(6-b)^2}

Square both sides:

208 = (6 - a)² + (6 - b)²

Let's also find the equation of the line AB. The y-intercept we know is 2, so in y = mx + b, b = 2. The slope is (6 - 2) / (6 - 0) = 4/6 = 2/3. So the equation of the line is: y = (2/3)x + 2. Since (a, b) lines on this line, we can put in a for x and b for y: b = (2/3)a + 2. Substitute this expression in for b in the previous equation:

208 = (6 - a)² + (6 - b)²

208 = (6 - a)² + (6 - (2/3a + 2))² = (6 - a)² + (-2/3a + 4)²

208 = a² - 12a + 36 + 4/9a² - 16/3a + 16 = 13/9a² - 52/3a + 52

0 = 13/9a² - 52/3a - 156

13a² - 156a - 1404 = 0

a² - 12a - 108 = 0

(a + 6)(a - 18) = 0

a = -6 or a = 18

We know a can't be negative so a = 18. Plug this back in to find b:

b = 2/3a + 2 = (2/3) * 18 + 2 = 12 + 2 = 14

So point D has coordinates (18, 14).

8 0
3 years ago
Read 2 more answers
consider the equation a(4-x) =-3x + b What values of a and b make the solution of the equation x = -5
-BARSIC- [3]

Answer:

Step-by-step explanation:

hello :

put x = -5 in this equation : a(4-x) =-3x + b

a(4+5) =15 + b

9a = 15 +b

b = 9a - 15

the values of a and b is all order  pair :   ( a  ; 9a-15)  a real number

3 0
2 years ago
Devide. (x^3-8x^2+2•(x-3)
Helen [10]

Answer:

-6 because I did it on my calculator

5 0
3 years ago
What are the zeros of f(x)=x^2+x-20?
zzz [600]
F(x) = x² + x - 20 = x² + 5x - 4x - 20 = x(x + 5) - 4(x + 5) = (x + 5)(x - 4)

f(x) = 0 ⇔ (x + 5)(x - 4) = 0 ⇔ x + 5 = 0 or x - 4 = 0 ⇒ x = -5 or x = 4

Answer: C. x = -5 and x = 4.
3 0
3 years ago
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