Find the real solutions to the equation.<br> 312,500 = 4z^7

Michael is 5 years old than rui feng and. Vishal is thrice as old as micheal if rui feng is 3 years old find Michael present age

lorasvet [3.4K]

Answer:

a) Micheal's present age = 8 years old

b) The sum of their ages in 6 years time = 63 years.

Step-by-step explanation:

From the above question, we know that

Rui feng is 3 years old

We are told that

• Michael is 5 years old than Rui feng

Micheal's present age is calculated as:

= 5 + Rui feng's age

= 5 + 3 = 8 years

• Vishal is thrice as old as Micheal

Vishal's present age is calculated as

= 3(Micheal age)

= 3(8)

= 24 years.

The sum of their ages in six years time

= ( 3 + 6) +( 8 + 6) + ( 24 + 6)

= 18 + 15 + 30

= 63 years

Therefore, a) Micheal's present age = 8 years old

b) The sum of their ages in 6 years time = 63 years.

3 0

3 years ago

Which relationship describes angles 1 and 2? Select each correct answer. A)adjacent angles

Talja [164]

Hey there!

As you can see, they are lying on the same line.

When two angles are on the same straight line, they are adjacent.

Adjacent angles are supplmentary.

Adjacent angles= 180 degrees Supplementary= 180 degrees

They are choices "A" and "B".

I hope this helps!
~kaikers

6 0

3 years ago

(6x+y)(6x-7) What is the answer?

lys-0071 [83]

= 6x + 6x - 6x × 7 + 6xy - 7y

36x2 - 42x + 6xy - 7y

6 0

2 years ago

Mary states, If the diagonals of a parallelogram are congruent, then the parallelogram is a rectangle. Decide if her statement i

Mila [183]

The answer for apex would be true.

8 0

3 years ago

Read 2 more answers

Determine which of these sequences is an arithmetic sequence. Then determine the explicit formula that would be used to define t

vagabundo [1.1K]

6)

34, 43, 52, 61, ...

43-34 = 9; 52-43 = 9; 61-52 = 9

The difference between one term and the next is a constant so it is arithmetic sequence

first term: a = 34

difference: d = 9

so the formula:

$a_n=a+d(n-1)\\\\a_n=34+9(n-1)\\\\a_n = 34+9n-9\\\\\underline{a_n=9n+25}$

7)

10, 6, 2, -2, ...

6-10 = -4; 2-6 = -4; -2-2 = -4

The difference between one term and the next is a constant so it is arithmetic sequence

first term: a = 10

difference: d = -4

so the formula:

$a_n=a+d(n-1)\\\\a_n=10+(-4)(n-1)\\\\a_n = 10-4n+4\\\\\underline{a_n=-4n+14}$

8)

-3, -10, -17, -24, ...

-10-(-3) = -7; -17-(-10) = -7; -24-(-17) = -7

The difference between one term and the next is a constant so it is arithmetic sequence

first term: a = -3

difference: d = -7

so the formula:

$a_n=a+d(n-1)\\\\a_n=-3+(-7)(n-1)\\\\a_n =-3-4n+7\\\\\underline{a_n=-7n+4}$

9)

7, 8.5, 10, 11.5, ...

8.5-7 = 1.5; 10-8.5 = 1.5; 11.5-10 = 1.5

The difference between one term and the next is a constant so it is arithmetic sequence

first term: a = 7

difference: d = 1.5

so the formula:

$a_n=a+d(n-1)\\\\a_n=7+1.5(n-1)\\\\a_n =7+1.5n-1.5\\\\\underline{a_n=1.5n+5.5}$

10)

30, 22¹/₂, 15, 7¹/₂, ...

22¹/₂-30 = -7¹/₂; 15-22¹/₂ = -7¹/₂; 7¹/₂-15 = -7¹/₂

The difference between one term and the next is a constant so it is arithmetic sequence

first term: a = 30

difference: d = -7¹/₂

so the formula:

$a_n=a+d(n-1)\\\\a_n=30+(-7\frac12)(n-1)\\\\a_n =30-7\frac12n+7\frac12\\\\ \underline{a_n=-7\frac12n+37\frac12}$

6 0

2 years ago

Find the real solutions to the equation. 312,500 = 4z^7