Which equation has the solutions x = 1 plus-or-minus StartRoot 5 EndRoot? x2 + 2x + 4 = 0 x2 – 2x + 4 = 0 x2 + 2x – 4 = 0 x2 – 2
x – 4 = 0
2 answers:
Answer:
x^2 - 2x - 4 = 0.
Step-by-step explanation:
Written in factor form we have:
(x - ( 1 + √5)( x - (1 - √5)) = 0
(x - 1 -√5)( x - 1 +√5)) = 0 Expanding:
x^2 - x +√5x - x + 1 - √5 - √5x + √5 - 5 = 0
x^2 - 2x - 4 = 0.
Answer: D!!!!!!!
Step-by-step explanation:
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