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Levart [38]
3 years ago
5

Which equation has the solutions x = 1 plus-or-minus StartRoot 5 EndRoot? x2 + 2x + 4 = 0 x2 – 2x + 4 = 0 x2 + 2x – 4 = 0 x2 – 2

x – 4 = 0
Mathematics
2 answers:
ale4655 [162]3 years ago
7 0

Answer:

x^2 - 2x - 4 = 0.

Step-by-step explanation:

Written in factor form we have:

(x - ( 1 + √5)( x - (1 - √5)) = 0

(x - 1 -√5)( x - 1 +√5)) = 0        Expanding:

x^2 - x +√5x  - x + 1 - √5 - √5x + √5 - 5 = 0

x^2 - 2x - 4 = 0.

tester [92]3 years ago
4 0

Answer: D!!!!!!!

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

First, let's find the sequence:

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\lim_{n \to \infty} 4n= 4 \lim_{n \to \infty} n\\ \\ \lim_{n \to \infty} n=\infty\\ \\4\infty= \infty\\\\Hence\\\\ \lim_{n \to \infty} 4n=\infty

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3 years ago
What is the result when 124 is increased by 6.5%
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4 years ago
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