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Pavel [41]
3 years ago
11

If 2^x+4 = 2^3x-1, what is the value of x?

Mathematics
1 answer:
Ronch [10]3 years ago
3 0

Answer:

     x = 5/2

Step-by-step explanation:

2^x+4 = 2^3x-1

x + 4 = 3x - 1

3x - x  = 4 + 1

2x   = 5

     x = 5/2

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larisa86 [58]
To solve this we are going to use the average rate of change formula: A(x)= \frac{f(b)-f(a)}{b-a}
where
A(x) is the average rate of change of the function
f(a) is the position function evaluated at a
f(b) is the position function evaluated at b
a is the first point in the interval
b is the second point in the interval

We can infer for our problem that the first point is 3 and the second point is 6, so a=3 and b=6. Lets replace those values in our formula:
A(x)= \frac{f(b)-f(a)}{b-a}
A(x)= \frac{f(6)-f(3)}{6-3}
A(x)= \frac{6-6^2-2-(3-3^2-2)}{3}
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We can conclude that the average rate of change of the function f(x) = 1 x - x2 - 2 for <span>3 ≤ x ≤ 6 is -8</span>
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