Answer:
Perimeter of ABCD - Perimeter of PQRS = 4x + 2
Step-by-step explanation:
i. For rectangle ABCD;
length, l = 2x -3
width, w = 4x + 5
Perimeter of a rectangle = 2(l + w)
Perimeter of ABCD = 2((2x -3) + (4x + 5))
= 2(2x -3 + 4x + 5)
= 2(6x + 2)
Perimeter of ABCD = 12x + 4
ii. For rectangle PQRS;
length, l = x - 1
width, w = 3x + 2
Perimeter of a rectangle = 2(l + w)
Perimeter of PQRS = 2((x - 1) + (3x + 2))
= 2(x - 1 + 3x + 2)
= 2(4x + 1)
Perimeter of PQRS = 8x + 2
So that,
Perimeter of ABCD - Perimeter of PQRS = (12x + 4) - (8x + 2)
= 12x + 4 - 8x - 2
= 4x + 2
Perimeter of ABCD - Perimeter of PQRS = 4x + 2
Answer:
b 15
Step-by-step explanation:
Answer:
Second option,domain: negative infinity, 4 and range, negative infinity, 3
The domain are all the x's that you can input into a function. It looks like the function goes to all x's from negative infinity until it hits positive 4. that's why it is -infinity, 4 for the domain.
The range is all the y's that are outputted. As you can see, the function goes to all y's from negative infinity to 3.
Step-by-step explanation:
Answer: B
Step-by-step explanation:
Answer:
2√13
Step-by-step explanation:
B(1,4) T(4,6) what is BD
find BT
d=√(x2-x1)²+(y2-y1)²
d=√(4-1)²+(6-4)²
d=√3²+2²
d=√9+4
d=√13 this is haf the distance
BD=2d=2√13