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Andreas93 [3]
2 years ago
11

What is the slope of a line parallel to the line whose equation is y = 5x + 4?

Mathematics
1 answer:
Leviafan [203]2 years ago
8 0

Answer:

5

Step-by-step explanation:

y=mx+b

m=slope

in your equation y=5x+4, m=5

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Xavier is attempting to recreate a problem his teacher showed him in class. To do so, he creates the table below.
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3 years ago
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What is the cosecant of angle X?
givi [52]

Answer:

cscX = \frac{y}{x}

Step-by-step explanation:

using the trigonometric identity

cscX = \frac{1}{sinX}

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8 0
3 years ago
A line passes through the origin and has a slope of 1/2.
ArbitrLikvidat [17]

Answer:

(2, 1)

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goes 2 units to the right

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Final Answer: (2, 1)

8 0
2 years ago
2 exponent 5 + 4 • 4 =
mixer [17]

Answer:

36?

Step-by-step explanation:

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5 0
2 years ago
A ship leaves port on a bearing of 34.0 and travels 10.4 mi. the ship then turns due east and travels 4.6mi. how far is the ship
Natasha2012 [34]
A bearing of 34° corresponds to corresponding angle of θ=90-34=56°
The (x,y) values for the position of the ship after completing its first heading are:
x=(10.4cos 56)
y=(10.4sin56)

The trigonometric angle for θ=90-90=0
The (x,y) values for the postion of the ship after completing the second bearing is:
x=(10.4 cos56)+(4.6cos0)≈10.4 mi
y=(10.4sin56)+(4.6sin0)≈8.6mi

the distance from the port will therefore be:
d=√(10.4²+8.6²)≈13.5 miles

It trigonometric angles is:
θ=arctan(y/x)
θ=arctan(8.6/10.4)
θ≈39.6°
Thus the bearing angle is:
90-39.6=50.4°
6 0
3 years ago
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