Plz answer all or one thx
2 answers:
You might be interested in
Answer:
Step-by-step explanation:
If we draw a right triangle, it would have legs 6 and 2.
the way I get the subsequent term, nevermind the exponents, the exponents part is easy, since one is decreasing and another is increasing, but the coefficient, to get it, what I usually do is.
multiply the current coefficient by the exponent of the first-term, and divide that by the exponent of the second-term + 1.
so if my current expanded term is say 7a³b⁴, to get the next coefficient, what I do is (7*3)/5 <----- notice, current coefficient times 3 divided by 4+1.
anyhow, with that out of the way, lemme proceed in this one.
so, following that to get the next coefficient, we get those equivalents as you see there for the 2nd and 3rd terms.
so then, we know that the expanded 2nd term is 24x therefore
we also know that the expanded 3rd term is 240x², therefore we can say that
but but but, we know what "n" equals to, recall above, so let's do some quick substitution
Let x represent the number
.. 1 +3x . . . . . . one more than three times a number
.. x -5 . . . . . . . the number decreased by 5
.. 1 +3x < x -5 . . . . the relation specified by the problem statement
.. 2x < -6 . . . . . . . subtract x+1
.. x < -3 . . . . . . . . . divide by the coefficient of x. (Positive, so < stays the same.)
.. 1 +3x . . . . . . one more than three times a number
.. x -5 . . . . . . . the number decreased by 5
.. 1 +3x < x -5 . . . . the relation specified by the problem statement
.. 2x < -6 . . . . . . . subtract x+1
.. x < -3 . . . . . . . . . divide by the coefficient of x. (Positive, so < stays the same.)