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Delicious77 [7]
3 years ago
10

A store manager can spend at most $1,000 a day for operating costs and payroll. It costs $100 each day to operate the store and

$30 dollars a day for each employee. Use the following inequality to determine how many employees the manager can afford for the day, at most: 30x + 100 ≤ 1000
x ≥ 30
x ≥ 33
x ≤ 33
x ≤ 30
Mathematics
1 answer:
valina [46]3 years ago
7 0

Answer:

x\leq30

The store manager can afford not more than 30 employees.

Step-by-step explanation:

Given:

Maximum amount a store manager can spend in a day = $1,000

Fixed cost for  rate of operation for each day = $100

Salary for each employee per day = $30

If x employees are working in the store then the inequality to find the   maximum number of employees the store manage can afford i given as:

30x+100\leq1000

To solve for x.

Solution:

We have :

30x+100\leq1000

Subtracting both sides by 100.

30x+100-100\leq1000-100

30x\leq900

Dividing both sides by 30.

\frac{30x}{30}\leq\frac{900}{30}

∴ x\leq30

Thus, the store manager can afford not more than 30 employees.

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