Question

A store manager can spend at most $1,000 a day for operating costs and payroll. It costs $100 each day to operate the store and $30 dollars a day for each employee. Use the following inequality to determine how many employees the manager can afford for the day, at most: 30x + 100 ≤ 1000
x ≥ 30
x ≥ 33
x ≤ 33
x ≤ 30

Answer 1

Answer:

$x\leq30$

The store manager can afford not more than 30 employees.

Step-by-step explanation:

Given:

Maximum amount a store manager can spend in a day = $1,000

Fixed cost for  rate of operation for each day = $100

Salary for each employee per day = $30

If $x$ employees are working in the store then the inequality to find the   maximum number of employees the store manage can afford i given as:

$30x+100\leq1000$

To solve for $x$.

Solution:

We have :

$30x+100\leq1000$

Subtracting both sides by 100.

$30x+100-100\leq1000-100$

$30x\leq900$

Dividing both sides by 30.

$\frac{30x}{30}\leq\frac{900}{30}$

∴ $x\leq30$

Thus, the store manager can afford not more than 30 employees.