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Natasha2012 [34]
3 years ago
14

+ PRINCIPLES OF MATHEMATICS

Mathematics
1 answer:
GREYUIT [131]3 years ago
3 0

Answer:

$9,840

Step-by-step explanation:

Let the money earned from college be 'x'.

Given:

Total money earned from the two jobs = $50,450

Money earned at the store = 1250 + 4(Money earned at college)

∴ Money earned at the store = 1250 +4x

Now, total money earned by Erica is the sum of money earned at store and college. Therefore,

Total money = Money at store + Money at college

50450=1250+4x+x\\5x+1250=50450\\5x=50450-1250\\5x=49200\\x=\frac{49200}{5}=\$9840

Therefore, the money earned by Erica from her job at the college is $9,840.

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Answer:

(a) The probability tree is shown below.

(b) The probability that a person who does not use heroin in this population tests positive is 0.10.

(c) The probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d) The probability that a randomly chosen person from this population tests positive is 0.1249.

(e) The probability that a person is heroin user given that he/she was tested positive is 0.2234.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is a heroin user

<em>Y</em> = the test is correct.

Given:

P (X) = 0.03

P (Y|X) = 0.93

P (Y|X') = 0.99

(a)

The probability tree is shown below.

(b)

Compute the probability that a person who does not use heroin in this population tests positive as follows:

The event is denoted as (Y' | X').

Consider the tree diagram.

The value of P (Y' | X') is 0.10.

Thus, the probability that a person who does not use heroin in this population tests positive is 0.10.

(c)

Compute the probability that a randomly chosen person from this population is a heroin user and tests positive as follows:

P(X\cap Y)=P(Y|X)P(X)=0.93\times0.03=0.0279

Thus, the probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d)

Compute the probability that a randomly chosen person from this population tests positive as follows:

P (Positive) = P (Y|X)P(X) + P (Y'|X')P(X')

                  =(0.93\times0.03)+(0.10\times0.97)\\=0.1249

Thus, the probability that a randomly chosen person from this population tests positive is 0.1249.

(e)

Compute the probability that a person is heroin user given that he/she was tested positive as follows:

P(X|positive)=\frac{P(Y|X)P(X)}{P(positive)} =\frac{0.93\times0.03}{0.1249}= 0.2234

Thus, the probability that a person is heroin user given that he/she was tested positive is 0.2234.

6 0
3 years ago
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