ANSWER
Find out the how much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .
To proof
let us assume that the fluid should be drained and replaced with pure antifreeze be x .
As given
A radiator contains 10 quarts of fluid, 30% of which is antifreeze.
Now write 30% in the decimal form

Now write 60% in the decimal form

After drained and replaced the fluid with pure antifreeze than the quantity becomes = ( 10 - x )
The quantity of antifreeze is

The fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .
than the equation becomes

solyving
100x +300 - 30x = 600
70x = 300

x = 4.28 quarts (approx)
Hence 4.28 quarts (approx) fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .
Therefore the option (c.) is correct .
Answer:
my answer would be D. The stock closed lower than the opening price.
A = fruit juice 40%
B= 90% juice
then
30 gallons + A = 55• C/100
30 gallons + N • (40/100) = (30 + N)• (55/100)
Now solve this equation, for N
3000 + 40N = (30+N) •55
then
3000 - 1650 = 55N - 40 N = 15N
1350 = 15 N
then
N= 1350/15 = 90
Then answer is
Should be mixed 90 gallons of 40% fruit punch
<h3>Solution :-</h3>
➩ 70 = 12 + 9x - 2 ( x + 6 )
➩ 70 = 12 + 9x - 2x - 12
➩ 70 = 0 + 7x
➩ 70 = 7x
Here we can use 2 methods
Methods :-
- Trial and error method :- By adding,subtracting , multiplying or dividing the same variable or constant on LHS & RHS
- Transposing :- by transposing a term from LHS to RHS or RHS to LHS
• Trial and error
By dividing with 7 on both sides
➩ 70/7 = 7x/7
➩ x = 10
• Transposing
By transposing 7 from RHS. to LHS
➩ 70/7 = x
➩ x = 10
Hence , x = 10