Answer:
1.1515
Step-by-step explanation:
3.29x0.35=1.1515
Answer:
![\frac{7}{30}\approx0.23](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B30%7D%5Capprox0.23)
Step-by-step explanation:
Given:
Number of questions (N) = 16
Number of easy questions (E) = 8
Number of medium-hard questions (M) = 5
Number of hard questions (H) = 3
Now, the probability of getting the first question as easy question is given as:
![P(E1)=\frac{\textrm{Number of easy questions}}{\textrm{Total questions}}\\\\P(E1)=\frac{E}{N}=\frac{8}{16}=0.5](https://tex.z-dn.net/?f=P%28E1%29%3D%5Cfrac%7B%5Ctextrm%7BNumber%20of%20easy%20questions%7D%7D%7B%5Ctextrm%7BTotal%20questions%7D%7D%5C%5C%5C%5CP%28E1%29%3D%5Cfrac%7BE%7D%7BN%7D%3D%5Cfrac%7B8%7D%7B16%7D%3D0.5)
Now, probability of getting the second question as easy question is given as:
![P(E2)=\frac{\textrm{Number of easy questions left}}{\textrm{Total questions left}}\\\\P(E2)=\frac{E-1}{N-1}=\frac{7}{15}](https://tex.z-dn.net/?f=P%28E2%29%3D%5Cfrac%7B%5Ctextrm%7BNumber%20of%20easy%20questions%20left%7D%7D%7B%5Ctextrm%7BTotal%20questions%20left%7D%7D%5C%5C%5C%5CP%28E2%29%3D%5Cfrac%7BE-1%7D%7BN-1%7D%3D%5Cfrac%7B7%7D%7B15%7D)
Now, probability that the first two contestants will get easy questions is given by the product of
. So,
![P(2\ easy\ questions)=P(E1)\times P(E2)\\\\P(2\ easy\ questions)=\frac{1}{2}\times \frac{7}{15}\\\\P(2\ easy\ questions)=\frac{7}{30}\approx 0.23](https://tex.z-dn.net/?f=P%282%5C%20easy%5C%20questions%29%3DP%28E1%29%5Ctimes%20P%28E2%29%5C%5C%5C%5CP%282%5C%20easy%5C%20questions%29%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5Cfrac%7B7%7D%7B15%7D%5C%5C%5C%5CP%282%5C%20easy%5C%20questions%29%3D%5Cfrac%7B7%7D%7B30%7D%5Capprox%200.23)
Therefore, the probability that the first two contestants will get easy questions is ![\frac{7}{30}\approx0.23](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B30%7D%5Capprox0.23)