I assume you mean the inverse of the function? If so, here's the steps:
![y = 5x \\ x = 5y \\ \frac{x}{5} = y \\ {f}^{ - 1}(x) = \frac{x}{5}](https://tex.z-dn.net/?f=y%20%3D%205x%20%5C%5C%20x%20%3D%205y%20%5C%5C%20%20%5Cfrac%7Bx%7D%7B5%7D%20%20%3D%20y%20%5C%5C%20%20%7Bf%7D%5E%7B%20-%201%7D%28x%29%20%3D%20%20%5Cfrac%7Bx%7D%7B5%7D%20)
Hope this helps!
Commutative property.
Sense nothing really changed and they just moved.
Answer:
-1536
Step-by-step explanation:
By taking the general formula for the geometric sequence, we substitute the variables with the values of our sequence, finding -1536 as the 11th term
Answer:
0.9855 or 98.55%.
Step-by-step explanation:
The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:
![P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855](https://tex.z-dn.net/?f=P%28X%5Cleq%201%29%3DP%28X%3D0%29%2BP%28X%3D1%29%5C%5CP%28X%5Cleq%201%29%3D%281-p%29%5E%7B23%7D%2B23%2A%281-p%29%5E%7B23-1%7D%2Ap%5C%5CP%28X%5Cleq%201%29%3D%281-0.008%29%5E%7B23%7D%2B23%2A%281-0.008%29%5E%7B23-1%7D%2A0.008%5C%5CP%28X%5Cleq%201%29%3D0.8313%2B0.1542%5C%5CP%28X%5Cleq%201%29%3D0.9855)
The probability that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.
You need to add fractions, find the LCD and then combine.
Exact Form:
59/78
Decimal Form:
0.7564102