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Debora [2.8K]
4 years ago
15

I. The temperature is -3º. An hour later, it drops 6º and 2 hours later,

Mathematics
1 answer:
sineoko [7]4 years ago
6 0

Answer:

-3 - 6 = -9

-9 + 4 = -5

Step-by-step explanation:

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Write the fractions in order from least to greatest 1/5 - 2/3 + 5/8
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Itts gunna be 5/8 then 1/5 then 2/3 i believe :)
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4 0
4 years ago
Read 2 more answers
I forgot how to do this.... can somebody help?
slamgirl [31]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}



\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template in mind, let's see

3 units to the right, that means C/B = -3 so hmm C = -3 and B = 1 will do, -3/1 = -3

vertical stretch by 2, so A = 2
reflected over the x-axis, so that means is flipped upside-down, so A = -2 then

and shifted down by 3, do D  = -3

\bf f(x)={{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}\implies f(x)={{  -2}}(\mathbb{R})^{{{  1}}x-{{  3}}}-{{3}}\\\\\\ f(x)={{  -2}}(3)^{{{  }}x-{{  3}}}-{{3}}
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4 years ago
Look Ahead To find the new temperature, you found the sum of a positive anda negative integer. You can use a number line to help
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Let's begin by listing out the information given to us:

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Calculate the area of the irregular polygon shown below:
MAXImum [283]
That's the diagram..
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7/8m= -14 solve using the multiplicative interverse​
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Combine multiplied terms into a single fraction, Multiply all terms by the same value to eliminate fraction denominators and Simplify.

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