All categories

3 years ago

6 quarts = gallons Please i meed help answer fast

Mathematics

1 answer:

Tju [1.3M]3 years ago

5 0

Answer:

1 2/4 or 1.5

Explanation:

There are 4 quarts in a gallon, and 2 left over add 1/2 to the full gallon. So, 1 gallon, plus 2 quarts, which is equal to 1/2 gallon, is 1.5 gallons :D

Hope this helped!

You might be interested in

What is the equation of the parabola?

bogdanovich [222]

It Given the focus (h,k) and the directrix y=mx+b, the equation for a parabola is (y - mx - b)^2 / (m^2 +1) = (x - h)^2 + (y - k)^2.

6 0

3 years ago

Solve the linear system... y=-3x+5 and 5x-4y=-3

ivolga24 [154]

Answer:

x = 1 , y = 2

Step-by-step explanation:

Solve for substitution

5 0

3 years ago

If Michelle walked walked 5 meters, how many inches did she walk?

LenaWriter [7]

There are ~39 inch in 1 meter

39 x 5 = 195

Michelle walked ~195 inch.

hope this helps

6 0

4 years ago

Read 2 more answers

What is the period and midline?

OverLord2011 [107]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\

\end{array}\qquad$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\


\end{array}$

$\bf \begin{array}{llll}
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}
$

so if you notice yours $\bf \begin{array}{llll}
3.2cos&\left( \frac{5}{3}\theta \right)+&6.1\\
&\ \uparrow&\uparrow \\
&B&D 
\end{array}$

now.. normally the function $\bf 3.2cos&\left( \frac{5}{3}\theta \right)$
has a D value of 0, or no vertical shift, and the amplitude and the period simply make the wave taller and thinner, but the midline is still the x-axis

now, with D = 6.1, that moves the midline up vertically that much

now.. the period, well, B = 5/3, normal period of cosine is $2\pi$
so, the new period will be $\bf \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{5}{3}}\implies \cfrac{6\pi }{5}$

notice the picture below
the vertical shift by the D component, or 6.1, moved the midline to y = 6.1 :)

6 0

3 years ago

III

docker41 [41]

Answer:

8x+6=-8

x=-1,75

Step-by-step explanation:

8x+6=-8

8x=-8-6

8x÷8=-14÷8

x=1,75

3 0

3 years ago