A triangle is acute provided all the angles have a measure of less than 90 degrees.
1 answer:
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Answer:
19
Step-by-step explanation:
Let T be the set of positive integers less than 100 with a 9 in the ten's place.
T = {90, 91, 92, 93, 94, 95, 96, 97, 98, 99}
n(T) = 10
Let O be the set of positive integers less than 100 with a 9 in the one's place.
O = {9, 19, 29, 39, 49, 59, 69, 79, 89, 99}
n(O) = 10
The common element is 99.
The union of both sets is
Therefore, 19 positive integers are less than 100 those have at least one 9.
Answer:
k=5
Step-by-step explanation:
We are provided with function, f ( x ) = 3 + kx − 13
which is divided by x+4 gives 15.
Here,
since f(x) is divided by x+4 so we can put :
x+4 = 0
x= -4
Putting this in f(x) -----> f(-4)
f(x) = f(-4) = 3 () + k(-4) − 13
f(-4) = 3(16) - 4k - 13
f (-4) = 48 - 4k - 13 ------------------------------------------Equation 1
Since, when f(x) is divided by x+4 , the remainder is 15 so we can say,
f(-4) = 15
putting in equation 1
f (-4) = 15 = 48 - 4k - 13
48 -4k - 13 = 15
35 - 4k = 15
35 - 15 = 4k (Moving - 4k on right hand side and 15 on the left)
or 20 = 4k
or 4k = 20
k =