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AlexFokin [52]
3 years ago
12

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2h, and Car B traveled the distan

ce in 1.5 h. Car B traveled 15 mph faster that car A. How fast did Car B travel?
Mathematics
1 answer:
mote1985 [20]3 years ago
4 0
Let the speed of car B be x.
Car B is faster than car A 15mph so the speed of car A would be: x-15.
From the problem, we could come up with an equation:
2(x - 15) = 1.5x \\ x = 60
So car B was traveling at 60mph

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Three friends Kofi,Yaw and Musa are in partnership business in which Kofi and Yaw contributed 5/9 and 2/15 of the cost of 14000.
wlad13 [49]

Answer:

(a) Total = 45000

(b) Yaw, Musa and Kofi

Step-by-step explanation:

Given

Kofi =5/9

Yaw = 2/15

Musa = 14000

Solving (a): The cost of the business

First, we solve for the fraction of Musa

Musa + Kofi + Yaw = 1

Musa = 1 - (Kofi + Yaw )

Musa = 1 - (5/9 + 2/15)

Musa = 1 - (\frac{25+6}{45})

Musa = 1 - \frac{31}{45}

Musa = \frac{45 - 31}{45}

Musa = \frac{14}{45}

So, we have:

\frac{14}{45} * Total = 14000

Make Total the subject

Total = 14000 * \frac{45}{14}

Total = 1000 * 45

Total = 45000

Solving (b): Partners in ascending order

First, represent the fractions as decimals

Kofi =5/9 = 0.5556

Yaw = 2/15 = 0.1333

Musa = \frac{14}{45} = 0.3111

From the conversion above, the least is 0.1333 (Yaw), then 0.3111 (Musa), then 0.5556 (Kofi).

<em>So, the order is: Yaw, Musa and Kofi</em>

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Answer:

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Step-by-step explanation:

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Rewriting

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This is a hyperbola

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