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3 years ago

6

Una tira de tela blanca mide 120 metros, se la quiere pintar de tres colores, un octavo se pinta de rojo, un tercio del resto se

pinta de azul, ¿Cuántos metros se pintan de azul?

2 answers:

Lorico [155]3 years ago

8 0

Answer:

xdjdnsxsj ddsx 343 de43 43e 43e jrndj anser

Step-by-step explanation:

o-na [289]3 years ago

4 0

Answer:

35m

Step-by-step explanation:

120m

Rojo: 1/8 . 120m --- el resto son 7/8 . 120m

Azul: 1/3 . 7/8 . 120m = 7/24 . 120m = 7/2 . 10m = 70m / 2 = 35m

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Rename the number 650 in tens

Ad libitum [116K]

Answer (quite straightforward):

650

= 65 x 10

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3 years ago

Read 2 more answers

The boxplot below shows salaries for CPAs and Actuaries in a town. 30 40 50 60 70 80 90 100 Salary (thousands of $) Actuary CPA

MA_775_DIABLO [31]

Answer: 75%

Step-by-step explanation:

In order to answer this question, we have to know the meaning of a box plot. Boxplots are especially useful in statistical analysis and gives us a meaningful range of values. A box plot consists of 2 shapes, which are the box part and the extended lines. The short sides of the box and the vertical line in the middle of the box represent a certain percentage of the values. The vertical line in the boxplot is the median of your dataset. For example, according to the shape given in the question, the median value for CPA's is 50 and this is closer to the left side of the box. This means that the first half ogf the dataset (when ranked from the smallest to the greatest) is closer to each other. The sides of the box represent the values at the 25% and 75% of the values respectfully.

For example, if we have 100 values, we rank them in order and the 25th value corresponds to the left side of the boxplot (named first quartile), 50th value (which is also the median) corresponds the vertical line in the box and and the 75the value corresponds to the right side of the box (named third quartile).

The extended arms are calculated as accordingly: IQR=(3rd quartile value-1st quartile value). Left extended arm is first quartile-1.5*IQR and right extended arm is third quartile+1.5*IQR. However, this information is not directly related to this question.

Now, this question should seem simpler. The median salary of CPA is 50 and this is equal to left side of the Actuary boxplot, which corresponds to the 25% of actuaries. As a result, CPA median salary is less than 75% of the Actuaries (100%-25%).

3 0

3 years ago

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

3 years ago

Find the distance between points (2, 9) and (5, 4) to the nearest tenth

Troyanec [42]

Answer:

$Distance = 5.8$

Step-by-step explanation:

$d=\sqrt{(4-9)^{2} } { (5-2)} ^{2} \\$

$d = -5^{2} + 3^{2}$

$d= 25 + 9$

$d= \sqrt{34}$

$distance = 5.8$

3 0

3 years ago

Find the volume of the solid. The volume of the solid is ____ cubic centimeters

Illusion [34]

Is there a picture ?

6 0

3 years ago