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3 years ago

7

Data are collected about the amount of time, in minutes, each member of a dance troupe spend practicing. How does a single outli

er change the median of the collected data?
A single outlier doubles the value of the median. A single outlier does not affect the median. A single outlier causes the value of the median to move slightly toward the outlier. A single outlier causes the value of the median to move slightly away from the outlier.

1 answer:

Neporo4naja [7]3 years ago

4 0

A single outlier causes the value of the median to move slightly away

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Please answer within the next 7 min, giving 38 points of a ligament answer!

frosja888 [35]

The answer is choice C

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2 years ago

A research team is testing whether a fuel aditive increases a car's gas mileage. The maker of the additive claims that the addit

Thepotemich [5.8K]

Answer:

Yes there is sufficient evidence to reject the company's evidence

Step-by-step explanation:

From the question we are told that

The sample size is n = 25

The mean is $\= x = 5.3 \ mpg$

The standard deviation is $\sigma = 1.8 \ mpg$

The z-score is z = -1.94

The null hypothesis is $H_o : \mu = 6 \ mpg$

The alternative hypothesis is $H_a : \mu \ne 6$

Generally the p-value is mathematically evaluated as

$p-value = 2 * P( Z$

From the z table the area under the normal curve to the left corresponding to -1.94 is

$P( Z$

=> $p-value = 2 * 0.02619$

=> $p-value = 0.052$

Let assume the level of significance is $\alpha = 0.05$

Hence the $p-value > \alpha$ this mean that

The decision rule is

Fail to reject the null hypothesis

The conclusion is

There is sufficient evidence to reject the company's evidence

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3 years ago

A triangle is reflected across line l and then line m. If the lines intersect, what kind of isometry is this composition of refl

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The answer is glide reflection

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2 years ago

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An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t

USPshnik [31]

The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

$\displaystyle\int_a^bf(x)\,\mathrm dx$

Split up the interval $[a,b]$ into $n$ equal subintervals,

$[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]$

where $a=x_0$ and $b=x_n$ . Each subinterval has measure (width) $\dfrac{a-b}n$ .

Now denote the left- and right-endpoint approximations by $L$ and $R$ , respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are $\{x_0,x_1,\cdots,x_{n-1}\}$ . Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, $\{x_1,x_2,\cdots,x_n\}$ .

So, you have

$L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)$
$R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)$

Now let $T$ denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

$T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)$

Factoring out $\dfrac12$ and regrouping the terms, you have

$T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)$

which is equivalent to

$T=\dfrac12\left(L+R)$

and is the average of $L$ and $R$ .

So the trapezoidal approximation for your problem should be $\dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2$

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What is 18 is 50% of

Zielflug [23.3K]

What you would have to do is take the 18 and double it because 50% doubled is 100% so when you double 18 it is 36

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