Question

Helpppppppp meeeeeee

Answer 1

Answer:

$4x^5-5x^3-6x$

Step-by-step explanation:

Given: $(x^3-2x)(4x^2+3)$

To find: the product

Solution:

Use the property: Multiplication is distributive over addition that is $a(b+c)=ab+ac$

$\left ( x^3-2x \right )\left ( 4x^2+3 \right )=(x^3-2x)4x^2+(x^3-2x)3\\=4x^5-8x^3+3x^3-6x$

Add the like terms: $-8x^3,3x^3$

(Like terms are terms that have same variables of same powers)

So,

$\left ( x^3-2x \right )\left ( 4x^2+3 \right )=(x^3-2x)4x^2+(x^3-2x)3\\=4x^5-8x^3+3x^3-6x\\=4x^5-5x^3-6x$