Answer:
Yes, you can use this inequality to find the numbers of cars required.
Step-by-step explanation:
12 + 3n > 28 where n = the number of cars required
3n > 28 -12
3n > 16
n > 5 1/3
Greater than 5 1/3 gives 6 cars.
Add up all the lengths of the garden and you will be able to get the perimeter.
Answer:
6hours
Step-by-step explanation:
From the given information:
Suppose it took Karl x hours to retile her bathroom,
Then it will take Della 3 hours longer i.e (3+x) hours
If Della and Karl work together or will take them 2 hours
The objective is to determine how long it will take Delia to retile the bathroom alone?
∴



By cross multiplying, we have:
2(2x+3) = 3x+x²
4x + 6 = 3x + x²
3x + x² - 4x - 6
x² - x - 6 = 0
Using quadratic equation
x² -3x +2x - 6 = 0
x(x - 3) + 2(x - 3) = 0
(x +2) (x - 3) = 0
x + 2 = 0 or x - 3 = 0
x = -2 or x = 3
Since we are concerned about the positive integer,
Then, Karl = x = 3 hours while Della which is (3+x) = 3+3 = 6hours
Answer: A. A=(1000-2w)*w B. 250 feet
C. 125 000 square feet
Step-by-step explanation:
The area of rectangular is A=l*w (1)
From another hand the length of the fence is 2*w+l=1000 (2)
L is not multiplied by 2, because the opposite side of the l is the barn,- we don't need in fence on that side.
Express l from (2):
l=1000-2w
Substitude l in (1) by 1000-2w
A=(1000-2w)*w (3) ( Part A. is done !)
Part B.
To find the width w (Wmax) that corresponds to max of area A we have to dind the roots of equation (1000-2w)w=0 ( we get it from (3))
w1=0 1000-2*w2=0
w2=500
Wmax= (w1+w2)/2=(0+500)/2=250 feet
The width that maximize area A is Wmax=250 feet
Part C. Using (3) and the value of Wmax=250 we can write the following:
A(Wmax)=250*(1000-2*250)=250*500=125 000 square feets