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garri49 [273]
3 years ago
7

The median and the mean are both the middle data point. . O True O False

Mathematics
2 answers:
larisa86 [58]3 years ago
7 0
False because median means middle and mean means average
Komok [63]3 years ago
5 0

Answer: false median is the middle

Step-by-step explanation:

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Select the type of equations.<br> equivalent<br> inconsistent<br> consistent
ZanzabumX [31]
The answer is consistent
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Find the equation of perpendicular bisector of the lines with the given word (1,2) and (5,4) ​
Mandarinka [93]

Answer:

y = -2x + 4

Step-by-step explanation:

Slope: (4-2)/5-1) = 2/4 = 1/2

Slope of the perpendicular line: -2

y-intercept: 2 - (-2)(1) = 4

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3 years ago
Carlos has taken an initial dose of a prescription medication.
Marat540 [252]

Answer:

3.48 hours

Step-by-step explanation:

The equation is:

M(t)=20 e^{-0.86t}

Where

M(t) is the amount of medication remaining in mg

t is the time it takes, in hours

The questions asks HOW LONG it will take to make the remaining medication to 1 milligrams (1 mg)??

We have to substitute M(t) with "1" and find the corresponding value of "t". We will use natural log to solve this. Shown below:

M(t)=20e^{-0.86t}\\1=20e^{-0.86t}\\0.05=e^{-0.86t}\\Ln(0.05)=Ln(e^{-0.86t})\\Ln(0.05)=(-0.86t)Ln(e)\\t=\frac{Ln(0.05)}{-0.86}\\t=3.48

<u>Note: </u> Ln(e) = 1

This means, the amount of time it will take is about 3.48 hours

8 0
3 years ago
Select all of the correct solutions for the following equation
zhuklara [117]

Answer: a,b, and c are the correct solutions

Step-by-step explanation:

You are substituting each (x,y) for the equation given. They must equal the same on both sides.

5 0
3 years ago
A line includes the points (10,-5) and (-10,-1). What is the equation in slope intercept form?
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\bf (\stackrel{x_1}{10}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{-10}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-(-5)}{-10-10}\implies \cfrac{-1+5}{-20}\implies \cfrac{4}{-20}\implies -\cfrac{1}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-5)=-\cfrac{1}{5}(x-10) \\\\\\ y+5=-\cfrac{1}{5}x+2\implies y=-\cfrac{1}{5}x-3

8 0
3 years ago
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