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2 years ago

How to learn to divide

Mathematics

1 answer:

ElenaW [278]2 years ago

4 0

Answer:

EX. 210/6

Step 1. Set up the equation, 210/6

Step 2. Divide the first digit/number 6 x 30 = 180 210 - 180 = 30

Step 3. rewrite the equation that is left, 30/6 6 x 5 = 30 30 - 30 = 0

Step 4. Only if need be for another equation, repeat step 1 and 2 until you have your answer

The Answer to the equation 210/6 is 35

Try 426/6 by yourself, please don't use a calculator.

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3 years ago

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3 years ago

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C. 10 m/s

Step-by-step explanation:

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2 years ago

of 320 consumers polled, some purchase blu-ray movies, some only purchase movies on dvd, and some do both. if 300 people polled

Helga [31]

Answer:

20 people only buy dvds.

Step-by-step explanation:

There are two groups in this problem. One group of people that buys dvds and one that buys blu rays. The total amount of people who buy blu rays is 300, but there's an intersection between the groups and the size of this is 280 people who actually buy both. In order to find out how many people only buy DVDs we first need to figure out how many only buy blu-rays. That is:

people who only buy blu rays = people who buy blu rays - people who buys blu rays and dvds

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We can now calculate the amount of people who only buy dvds and that is:

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people who only buy dvds = 320 - (20 + 280) = 320 - 300 = 20 people

3 0

3 years ago

A scientist had 3 1/2 liters of vinegar. He poured 2/3 of the vinegar into beaker. He then used 3/5 of the vinegar in the beaker

valentinak56 [21]

Answer:

A)2100 ml

Step-by-step explanation:

Given total vinegar is 3 1/2 liters and the used vinegar is 3/5 of the vinegar in the beaker:

#First calculate the amount of vinegar not poured in the beaker:

$V_o=V_t-V_b\\\\=3\frac{1}{2}(1-\frac{2}{3})\\\\=1\frac{1}{6}$

#Calculate amount of vinegar used in experiment:

$V_b=\frac{2}{3}V_t=\frac{2}{3}(3\frac{1}{2})=2\frac{1}{3}\\\\V_u=\frac{3}{5}V_b=\frac{3}{5}\times 2\frac{1}{3}=1\frac{2}{5}$

#The unused vinegar is therefore calculated by subtracting the used vinegar from the total at the start of the experiment:

$V_r=V_t-V_u\\\\=3\frac{1}{2}-1\frac{2}5}\\\\=2\frac{1}{10}\times 1000\ ml\\\\=2100\ ml$

Hence, the unused vinegar is 2100 ml

8 0

3 years ago