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2 years ago

I WILL GIVE BRAINLIST AND 50 POINTS

Mathematics

2 answers:

algol132 years ago

8 0

Answer:

Step-by-step explanation:

Alisiya [41]2 years ago

7 0

Step-by-step explanation:

A proportional relationship graph would show that the points can be arranged in a line that passes through the origin.

All of the points in Graphs B, C and D cannot be connected in 1 straight line, hence they are not proportional relationships.

Only Graph A shows a proportional relationship.

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Find all the missing angles:

siniylev [52]

Step-by-step explanation:

this is the answer in the picture

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3 years ago

Find dy/dx by implicit differentiation. 4x2 + 5xy - y2 = 6

Vlada [557]

4x^2 + 5xy - y^2 = 6
Implicitly differentiating both sides,
4(2x) + 5(x y' + y) - 2yy' = 0

where y' = dy/dx

8x + 5xy' +5y -2yy' = 0

combining y' terms
y' (5x-2y) +8x +5y = 0

y'(5x-2y) = -(8x+5y)

dy/dx = -(8x+5y)/(5x-2y)
or
dy/dx = (8x+5y)/(2y-5x)

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3 years ago

I need help with this question ASAP

zubka84 [21]

Answer:

A, D, and I think E

I hope this helps :)

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3 years ago

Find the lateral area of this square based pyramid. 10 ft 10 ft [ ? jft?

german

Answer:

200. 200 200 200 200 200 is the answer

6 0

3 years ago

Read 2 more answers

A 90 percent confidence interval is to be created to estimate the proportion of television viewers in a certain area who favor m

Dominik [7]

Answer:

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The width of the interval is:

$W = 2z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this sample:

Two 90% intervals, with different lenghts. So both have the same values for z an $\pi$

Interval A:

9000 viewers.

So the width is

$W_{A} = 2z\sqrt{\frac{\pi(1-\pi)}{9000}}$

Interval B:

100 viewers

So the width is

$W_{B} = 2z\sqrt{\frac{\pi(1-\pi)}{1000}}$

Relationship between the widths:

$R = \frac{W_{A}}{W_{B}} = \frac{2z\sqrt{\frac{\pi(1-\pi)}{9000}}}{2z\sqrt{\frac{\pi(1-\pi)}{1000}}} = \frac{\sqrt{1000}}{\sqrt{9000}} = \frac{\sqrt{1}}{\sqrt{9}} = \frac{1}{3}$

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

8 0

3 years ago