All categories

3 years ago

What is 2/3 plus 1/6

Mathematics

2 answers:

Varvara68 [4.7K]3 years ago

5 0

Answer:

That would be 5/6

Step-by-step explanation:

You multiply the denominator and the numerator by 2 to get a common denominator of 6. You add the 4 to the 1 to get 5/6

Paladinen [302]3 years ago

3 0

Answer:

5/6

Step-by-step explanation:

2/3=4/6

4/6+1/6=5/6

You might be interested in

The Oregon Trail is 2197 miles long How long would it take a covered wagon traveling 20 miles a day to complete the trip? Write

Harlamova29_29 [7]

2197/20 = 109.85
the answer is 109 17/20

hope this helps

4 0

3 years ago

Read 2 more answers

If x < 5, then which of the following must be true?

pychu [463]

Answer:

2 answers

Step-by-step explanation:

8 0

3 years ago

Una persona va a solicitar un prestamo en el banco de 35,000 pesos, con una tasa de interes del 3% va a pagar en 5 años cual ser

Nuetrik [128]

Respuesta:

5250

Explicación paso a paso:

Dado que :

Importe del préstamo, principal, p = 35000

Tasa de interés, r = 3% = 0.03

Tiempo, t = 5 años

Usando la fórmula de interés simple:

Interés = principal * tasa * tiempo

Interés = 35000 * 0.03 * 5

Intereses = 5250 pesos

8 0

3 years ago

Find LCM of: x2 - 9, 3x3 + 81

VikaD [51]

Answer:

$\boxed{\pink{\sf (x + 3) \ is\ the \ LCM . }}$

Step-by-step explanation:

Given two expressions ,

$\qquad (1)\: x^2 - 9 \\\\ \qquad (2)\:3x^3 + 81$

And , we need to find the LCM , that is lowest common factor . So , let's factorise them seperately .

Factorising x² - 9 :- 

$= x^2 - 9 \\\\= x^2 - 3^2 \\\\ \red{= (x+3)(x-3)} \qquad\bf [Using \ a^2-b^2 = (a+b)(a-b) ]$

Factorising 3x³ + 81 

$= 3x^3 + 81\\\\= 3(x^3+27) \\\\= 3( x^3+27) \\\\ = 3(x^3+3^3) \\\\ \red{= 3 [ (x+3)(x^2+9-3x) ] } \qquad \bf{[ Using \ a^3+b^3=(a+b)(a^2+b^2-ab) ] }$

Hence we can see that (x+3) is common factor in both expressions.

Hence the LCM is ( x+3 ) .

8 0

3 years ago

HELPPPP WHATS THE LATERAL AREA

AVprozaik [17]

Answer:

3cm

Step-by-step explanation:

6 0

3 years ago