Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
Answer:
Four
Step-by-step explanation:
Let's expand and see how many nonzero terms:
⇒ (x+4)(2x²+3x+9)-3(x³-2x²+7x)=
⇒ 2x³ + 3x² + 9x + 8x² + 12 + 36 - 3x³ + 6 x² - 21 x=
⇒ - x³ + 17x² - 12x + 12
As we see the expression has four nonzero terms
10x10x10x10=10^4
10x10x10x10=10,000
6x10^5=6x100000
6x10^5=600000
That would be 0.24(0.4). First, estimate the result: 0.24 is about 1/4, and (1/4)(0.4) is about 0.1.
0.24(0.4) = 0.096 (which agrees with the estimated answer, 0.1).
