Answer:
After 1.5 second of throwing the ball will reach a maximum height of 44 ft.
Step-by-step explanation:
The height in feet of a ball after t seconds of throwing is given by the function
h = - 16t² + 48t + 8 .......... (1)
Now, condition for maximum height is
{Differentiating equation (1) with respect to t}
⇒ 
seconds.
Now, from equation (1) we get
h(max) = - 16(1.5)² + 48(1.5) + 8 = 44 ft.
Therefore, after 1.5 seconds of throwing the ball will reach a maximum height of 44 ft. (Answer)
Answer:
27 feet
Step-by-step explanation:
We are told in the question that a lot is rectangular in shape
The perimeter of a rectangle
= 2(L + W)
= 2L + 2W
Where
L = Length of the rectangle
W = Width of the rectangle
From the question,
P = 66 feet
The length is 3 times more than 4 times the width
L = 3 + (4 × W)
= 3+ (4W) = 3 + 4W
Hence,
P = 2L + 2W
66 = 2(3 + 4W) + 2W
66 = 6 + 8W + 2W
Collect like terms
66 - 6 = 8W + 2W
60 = 10 W
W = 60/10
W = 6
The Width of the rectangular lot = 6 feet
To find the length
Perimeter = 2L + 2W
Perimeter - 2W = 2L
L = Perimeter - 2W/2
L = 66 - 2(6)/2
L = 66 - 12/2
L = 54/2
L = 27
Therefore the Length of the rectangular lot = 27 feet
Answer:
can you show diagram then i will edit answer
Step-by-step explanation:
Answer:
2.3,2.03,2.003
Step-by-step explanation:
i need points
