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Paul [167]
3 years ago
9

Please find the slope

Mathematics
1 answer:
zloy xaker [14]3 years ago
5 0

Answer:

-x

Step-by-step explanation:

for every one you go right you do down by 1 so the fraction would be

change in y ÷ change in x = Gradient

    -1   ÷ 1 = -1  

Gradient = -1

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Rewrite 8 1/2 as an improper fraction ​
g100num [7]

Answer:

17/2

Step-by-step explanation:

8 × 2 = 16 adding 1 = 17

3 0
3 years ago
3. Determine which of the following pairs is an adjacent side for quadrilateral MOLE below.
yKpoI14uk [10]

Pairs which is Adjacent side for quadrilateral MOLE is given below.

Step-by-step explanation:

Given:

Quadrilateral MOLE

Pair of adjacent sides of the quadrilateral.

Adjacent sides have one vertex common.

Option A: MO and LE

These sides does not have common vertex.

MO and LE are opposite sides in the quadrilateral MOLE.

It is not true.

Option B: EO and ME

In the quadrilateral, ME is not a side.

So it is not true.

Option C: LE and OL

In the quadrilateral, OL is not a side.

So it is not true.

Option D: ML and LE

These sides have common vertex L.

Therefore ML and LE are pair of adjacent sides.

It it true.

Hence ML and LE is a pair of adjacent side for quadrilateral MOLE.

7 0
3 years ago
Write a polynomial (x+6)(x-2)(x-1)
sasho [114]
<span>Write a polynomial (x+6)(x-2)(x-1)
</span><span><span><span>x<span><span>​3</span><span>​​</span></span></span>+3<span>x<span><span>​2</span><span>​​</span></span></span>−16x+12</span>I Hope this help</span>
7 0
3 years ago
Read 2 more answers
Suppose that A is the set of sophomores at your school and B is the set of students in discrete mathematics at your school. Expr
Anarel [89]

Answer:

Suppose that A is the set of sophomores at your school and B is the set of students in discrete mathematics at your school.

a) It is the intersection A ∩ B

b) This is the difference A − B.

c) It is the union A ∪ B.

                                   ---    ---

d) It can be shown as A ∪ B. (bar over A and B both)

5 0
3 years ago
Find the standard form of the equation of the parabola with the given characteristics. Vertex: (-6, 1); focus: (-6, 0)
GREYUIT [131]

Answer: (x+6)^2=-4(y-1)

Step-by-step explanation:

Given

Vertex of the parabola (-6,1)

Focus of the parabola (-6,0)

As the x coordinate of vertex and focus is same and focus lie below the vertex, therefore the parabola is the type of

(x+6)^2=-4a(y-1)

distance between Vertex and focus is 1 unit

\therefore a=1

Parabola becomes

\Rightarrow (x+6)^2=-4(y-1)

8 0
3 years ago
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