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likoan [24]
3 years ago
6

What are the closest integers that the square root of 300 is in between?

Mathematics
1 answer:
cricket20 [7]3 years ago
6 0
They are 17 and 18! The square root of 300 is 17.32 (rounded to the nearest tenth). The integer (or whole number) below that is 17. The whole number above it is 18. Therefore, the square root of 300 is between them.
Hope that helps! :)
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s344n2d4d5 [400]

Answer:

A. = 20 in²

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C. = 29.5 ft²

D. = 36 ft²

E. = 28 ft²

Step-by-step explanation:

A. Formula = A = (h_b b)/2 = base 10 ft height_b= 4ft = 20 ft²

B. We have a rectagnle and a triangle:  Formula: A = lw

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C. we have 2 rectagnle and a triangle: First the small recangle: A= lw = A = 1ft x 2ft = 2ft²

Second rectangle: 5 ft x 4 ft = 20 ft²

Right angeled triangle Formula: (ab)/2 = 3 ft x 5 ft = 7.5 ft²

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D. is a rectangle and a triangle: 8 ft x 3 ft = 24ft²

the triangle 8 ft x 2ft = 12 ft²; add 24 ft²+12 ft² = 36ft²

E. is a right-angled triangle (see fromula above) =  (14 ft x 4 ft)/2 = 28ft²

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Answer:

\displaystyle d = \sqrt{29}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
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<u>Algebra II</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

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<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

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  2. Add/Subtract:                       \displaystyle d = \sqrt{(2)^2+(-5)^2}
  3. Exponents:                           \displaystyle d = \sqrt{4+25}
  4. Add:                                      \displaystyle d = \sqrt{29}
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