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kiruha [24]
3 years ago
7

Heres another questions, hope someone can help me.

Mathematics
1 answer:
sleet_krkn [62]3 years ago
3 0
2x18=36cm
you do 2cm times 18cm to get to your final answer

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This diagram of a rectangular city park was drawn using a scale of 1 centimeter to 20 meters
I am Lyosha [343]

Answer:

Scale factor for the drawing from actual park = \frac{1}{20}

Area of the actual park = 1200 cm²

Step-by-step explanation:

Length of the rectangular city park = 5 cm

Width of the rectangular park = 6 cm

Using scale factor 1 cm = 20 meters

Scale factor = \frac{\text{length of the park in drawing}}{\text{Actual length of park}}=\frac{1}{20}

\frac{5}{\text{Actual length of park}}=\frac{1}{20}

Actual length = 5 × 20 = 100 meters

Actual width = 6 × 20 = 120 meters

Area of the rectangular park = length × width

                                               = 100 × 120

                                               = 1200 square meters

Therefore, Scale factor from actual length to the length in drawing = 1 : 20

Area of the rectangular park = 1200 square feet

7 0
3 years ago
You can pay $10 for 2 movie tickets assuming the same rate , how much would you pay for 5 movie tickets ?
11Alexandr11 [23.1K]

Answer:

If we assume every 2 movie tickets is $10 then every one ticket would be $5. Assuming this to be true then 5 tickets is $25.

StepByStep Explanation:

movie tickets = t

2t=10

t=5

5t=?

5(5)=?

25=?

?=25


8 0
3 years ago
Ben has a cell phone plan that provides 200 free minutes each month for a flat rate of $39. For any minutes over 200, Ben is cha
faltersainse [42]

Answer:

\left\{\begin{matrix}39 & x\leq 200\\ 39+(x-200)\times 0.35 & x>200\end{matrix}\right.

Step-by-step explanation:

We are given that Ben has a cell phone plan that provides 200 free minutes each month for a flat rate of $39.

We are also told that For any minutes over 200, Ben is charged $0.35 per minute.

let x  be the minutes used each month

So, if x\leq 200

So, coat will be $39

If x>200

So, Ben is charged $0.35 per minute

So, when x>200

So, charge = 39+(x-200)\times 0.35

So, the piecewise functions accurately represents charges based on Ben's cell phone :

\left\{\begin{matrix}39 & x\leq 200\\ 39+(x-200)\times 0.35 & x>200\end{matrix}\right.

4 0
3 years ago
Read 2 more answers
The image shown below shows the first 3 stages of a pattern.
alisha [4.7K]

Answer:

A. 44

Step-by-step explanation:

Well, there is something interesting we see in this image. The number of tiles add by 2 every time which makes the 22nd the answer because 2 x 22 is 44

7 0
2 years ago
Read 2 more answers
Joey's strategy for his first marathon (26.2 miles)was to run 2 miles, walk 1 mile, run 2 miles, walk 1 mile, and continue this
lana [24]
<h3>Answer:  275.2 minutes</h3>

========================================================

Explanation:

We have this sequence

(2+1)+(2+1)+(2+1)...

Effectively, we're repeating "2+1" over and over.

We can see that

  • 2+1 = 3
  • (2+1)+(2+1) = 3+3 = 6
  • (2+1)+(2+1)+(2+1) = 3+3+3 = 9

Each time we add on another copy of (2+1), we're adding on 3

Dividing 26.2 over 3 gets us (26.2)/3 = 8.733 approximately

If we had 8 copies of (2+1) added together, then we would get

8*(2+1) = 8*3 = 24

This is 26.2-24 = 2.2 miles short of his goal.

He'll need to run 2 more miles, plus walk another 0.2 of a mile

----------------------------------------------------

In summary so far, Joey will run 8+1 = 9 sections (two miles each) and walk 8 sections that are 1 mile each. At the very end, he'll walk 0.2 miles to finish the race. Each running and walking section is alternated of course.

Since he runs 9 sections, each 2 miles, that accounts for 9*2 = 18 miles.

His running pace is 8 minutes per mile, so this means he has run for 8*18 = 144 minutes. This is just the running part and not the walking part.

Let A = 144 so we can use it later.

----------------------------------------------------

He walks 8 sections of 1 mile each. His walking pace is 16 minutes per mile. This must mean he spends 8*16 = 128 minutes on this walking portion.

Then for the last 0.2 mile section he walks, we can solve the proportion below

(1 mile)/(16 min) = (0.2 miles)/(x min)

1/16 = 0.2/x

1*x = 16*0.2

x = 3.2

He spends 3.2 minutes walking the remaining 0.2 of a mile at the end.

So his total walking time is 128+3.2 = 131.2 minutes.

Let B = 131.2

-----------------------------------------------------

To wrap things up, we'll add up the results of each of the previous two sections.

A = total running time = 144 min

B = total walking time = 131.2 min

C = total marathon time

C = A+B

C = 144+131.2

C = 275.2 minutes

This converts to 275 min, 12 sec.

This is also equivalent to 4 hrs, 35 min, 12 sec.

5 0
3 years ago
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