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3 years ago

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jack has a piece of red ribbon that is two times as long as his piece of blue ribbon. he says that he can use two different equa

tion to find out how long his piece of red ribbon is compared to his piece of blue ribbon is. is he correct? explain his reasoning

1 answer:

morpeh [17]3 years ago

5 0

He is correct. since it is double the amount of B, he can do Bx2, or b+b

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Simplify (3x + 5) + (2x - 9) - (4x+3).<br><br><br> A.) X-7<br> B.) -X-7<br> C.) 9x1<br> D) 9x1

erica [24]

Answer:

x -7

Step-by-step explanation:

(3x + 5) + (2x - 9) - (4x+3)

3x + 5 + 2x - 9 -4x -3

x -7

8 0

3 years ago

Read 2 more answers

Help, please!! What is mA?

Inga [223]

Answer:

38°

Step-by-step explanation:

The measure of required angle can be obtained by using cosine law.

From the given triangle we find that:

a = 5, b = 3, c = 7,

Since,

cos (A) = (b^2 +c^2 - a^2) /2bc

Therefore,

cos (A) = (3^2 + 7^2 - 5^2) /(2*3*7)

cos (A) = (9 + 49 - 25) /(42)

cos (A) = (33) /(42)

cos (A) = 0.785714286

A = arccos(0.785714286)

A = 38.213210675°

A = 38°

4 0

3 years ago

Help please. Im trying to do my homework but i don't understand how to.

Neko [114]

V = (4/3) pi r^3

9. V = (4/3)(3.14)(7.62)^3 = 1852.4 meters^3
10. V = (4/3)(3.14)(33/2)^3 = 18,807.0 inches^3
11. V = (4/3)(3.14)(18.4/2)^3 = 3260.1 feet^3
12. V = (4/3)(3.14)(sqrt3)/2)^3 = 2.7 cm^3
13. C = 2*pi*r ; 24 = 2 * 3.14 * r; 24/6.28 = r ; r = 3.82
V = (4/3)(3.14)(3.82)^3 = 233.4 in^3
14.V = (4/3)(3.14)(35.8)^3 = 192,095.6 mm^3

I can't read # 15 but follow the steps above.

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3 years ago

Eric traveled to three cities on a single highway. The distance from his original location to the first city was 100 miles more

Anna35 [415]

Answer:

B

Step-by-step explanation:

*cough cough*

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3 years ago

Graph f(x) =-2x^+16x-30 by factoring to find the solutions, then find the coordinates of the vertex, and the axis of symmetry. I

fredd [130]

Answer:

<em>Observe attached image</em>

<em>Function zeros:</em>

(3, 0), (5, 0)

<em>Vertex:</em>

(4, 2)

<em>Axis of symmetry:</em>

<em> $x =4$ </em>

Step-by-step explanation:

<u>First factorize the function</u>

$f (x) = -2x ^ 2 + 16x-30$

<em>Take -2 as a common factor.</em>

$-2(x ^ 2 -8x +15)$

<em>Now factor the expression $x ^ 2 -8x +15$ </em>

You must find two numbers that when you add them, obtain the result -8 and multiplying those numbers results in 15.

These numbers are -5 and -3

Then we can factor the expression in the following way:

$f (x) = -2(x-5)(x-3)$

<em><u>The quadratic function cuts the x-axis at </u></em><em>x = 3 and at x = 5.</em>

Now we find the coordinates of the vertex.

For a function of the form $ax ^ 2 + bx + c$ the x coordinate of its vertex is:

$x = \frac{-b}{2a}$

In the function $f (x) = -2x ^ 2 + 16x-30$

$a = -2\\b = 16\\c = 30$

<u>Then the vertice is:</u>

$x = \frac{-16}{2(-2)}\\\\x = 4$

The y coordinate of the symmetry axis is

$y = f (4) = -2 (4) ^ 2 +16 (4) -30\\\\y = 2$

The axis of symmetry is a vertical line that cuts the parabola in two equal halves. This axis of symmetry always passes through the vertex.

<u>Then the axis of symmetry is the line</u>

$x = 4$

<u>The solutions and the vertice written as ordered pairs are:</u>

<em>Function zeros:</em>

(3, 0), (5, 0)

<em>Vertex:</em>

(4, 2)

6 0

3 years ago