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Ludmilka [50]
3 years ago
14

Sasha wants to buy some dresses over the Internet. Each dress costs $7.15 and has a shipping cost of $9.95 per order. If Sasha w

ants to spend no more than $60 for her dresses, which inequality shows the maximum number of dresses, p, that she can buy?
Mathematics
2 answers:
hodyreva [135]3 years ago
8 0
9.95+7.15p<=(less than or equal to)60, so p <= 7
Mars2501 [29]3 years ago
3 0
The inequality that shows the maximum number of dresses she can buy is $7.15p+$9.95=$60 the maximum # of dresses she can buy is 7
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The first few steps in deriving the quadratic formula are shown.
Kisachek [45]

In the first few steps for deriving the quadratic formula left side of the equation due to the distributive property for balancing the equation.

<h3>What is quadratic equation?</h3>

A quadratic equation is the equation in which the highest power of the variable is two.

Here, The first few steps in deriving the quadratic formula are shown in the table.

Use the substitution property of equality to solve it further,

-c=-ax² +bx

Now factor out the term a, to solve further as,

    - c = a (x² + b/a x)

for half of the b value and square it to determine the constant of the perfect square trinomial as,

     (b/2a)² = b²/4a²

Now  the distributive property needs to be applied to determine the value to add to the left side of the equation to balance the sides of the equation.

  -c + b²/4a² = a(x² + b/a x + b²/4a² )

Thus, the distributive property needs to be applied to determine the value to add to the left side of the equation to balance the sides of the equation.

Learn more about Quadratic equation from:

brainly.com/question/14336752

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7 0
2 years ago
A sheet of paper 90 cm-by-66 cm is made into an open box (i.e. there's no top), by cutting x-cm squares out of each corner and f
NNADVOKAT [17]

Answer:

26 - \sqrt{181} cm

Step-by-step explanation:

The volume of the box is:

V = height * length * width

V = x*(66 - 2*x)*(90 - 2*x)

V = (66*x - 2*x^2)*(90 - 2*x)

V = 5940*x - 132*x^2 - 180*x^2 + 4*x^3

V = 4*x^3 - 312*x^2 + 5940*x

where x is the length of the sides of the squares,  in cm.

The mathematical problem is :

Maximize: V = 4*x^3 - 312*x^2 + 5940*x

subject to:

x > 0

2*x < 66 <=> x < 33

In the maximum, the first derivative of V, dV/dx, is equal to zero

dV/dx = 12*x^2 - 624*x + 5940

From quadratic formula

x = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}

x = \frac{624 \pm \sqrt{(-624)^2 - 4(12)(5940)}}{2(12)}

x = \frac{624 \pm \sqrt{104256}}{24}

x = \frac{624 \pm \sqrt{2^6*3^2*181}}{24}

x = \frac{624 \pm 8*3*\sqrt{181}}{24}

x_1 = \frac{624 + 24*\sqrt{181}}{24}

x_1 = 26 + \sqrt{181}

x_2 = \frac{624 - 24*\sqrt{181}}{24}

x_2 = 26 - \sqrt{181}

But x_1 > 33, then is not the correct answer.

5 0
3 years ago
Conner scored 4,370 points in a game.Amy scored 1,089 fewer points then Conner how many points did Amy scored
statuscvo [17]
SOLUTION:

Connor's score = 4, 370 points

Amy's score = Connor's score - 1, 089

Amy's score = 4, 370 - 1089

Amy's score = 3, 281 points

Therefore, Amy scored 3, 281 points.

Hope this helps! :)
Have a lovely day! <3
3 0
3 years ago
Working on an AP Calc redo! I know the correct answer but don't know how to get there. Definite Integrals!
eduard
Depends on the calculator you have at your disposal. If it's one of the TI-83 series, you can use the built-in 'fnint' function.

https://brownmath.com/ti83/integr.htm
8 0
3 years ago
Find the Area. Simplify your answer.​
Vaselesa [24]

Answer:

Area = 9x^2 square units

Step-by-step explanation:

<u>Key skills needed: Area of a parallelogram</u>

1) This shape is a parallelogram, and the way to find the area of a parallelogram is:

                                A = bh

A = area

b = base (the side at the bottom

h = the height ( the length that runs from one side to another and makes a right angle)

2) The base (b) would be 3x. The height (h) would also be 3x

3) This means A = 3x(3x)

3 times 3 is 9 --> and x times x is x^2

Therefore the area is --> 9x^2

<em>Hope you understood and have a nice day!! :D</em>

5 0
3 years ago
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