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2 years ago

X to the power of 2 subtract 3x for x=4

Mathematics

1 answer:

Helen [10]2 years ago

6 0

First, X^2 while x is 4 =4^2, which is 4x4, which is 16
3X while x is 4 is 12. 16-12=4. So the answer is 4

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An article reported that what airline passengers like to do most on long flights is rest or sleep; in a survey of 3697 passenger

maw [93]

F(x,n,p)=C(n,x)p^x*(1-p)^(n-x)
n=9, p=0.8 =>
f(x,9,0.8)=C(9,x)0.8^x*(0.2)^(9-x)

The function f(x,9,0.8) is then calculated using the above formula
x f(x)
0 0.0000001 0.0000182 0.0002953 0.0027534 0.0165155 0.0660606 0.1761617 0.3019908 0.3019909 0.134218

Check Sum f(x), [x=0,9] = 1.0 ok

4 0

2 years ago

The probability that it will rain on Thursday is 67%. What is the probability that it won’t rain on Thursday? Express your answe

kondaur [170]

Answer:

33%

Step-by-step explanation:

Since the probability of rain on Thursday is 67%, the probability of no rain on Thursday is 100% - 67% = 33%.

4 0

1 year ago

F(x)= 3x-3, g(x) =5x-9 find (f-g)(x)

marusya05 [52]

Answer:

Step-by-step explanation:

The answer is A

6 0

2 years ago

Find the height of the building below by using your knowledge of trigonometry.

Lilit [14]

Answer:

50 $\sqrt{3}$

Step-by-step explanation:

The figure represents a 30-60-90 special triangle

in this special right triangle the measure of sides lengths is represented by

a, a $\sqrt{3}$ , and 2a

The side length that sees angle measure 30 is represented by a and here we see a = 50m

The height of the building, which sees angle measure 60, is equal to

50 $\sqrt{3}$

5 0

2 years ago

The joint probability mass function of XX and YY is given by p(1,1)=0p(2,1)=0.1p(3,1)=0.05p(1,2)=0.05p(2,2)=0.3p(3,2)=0.1p(1,3)=

inessss [21]

Answer:

P(Y=1|X=3)=0.125

Step-by-step explanation:

Given :

p(1,1)=0

p(2,1)=0.1

p(3,1)=0.05

p(1,2)=0.05

p(2,2)=0.3

p(3,2)=0.1

p(1,3)=0.05

p(2,3)=0.1

p(3,3)=0.25

Now we are supposed to find the conditional mass function of Y given X=3 : P(Y=1|X=3)

P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)

P(X=3)=p(3,1) +p(3,2) +p(3,3)

P(X=3)=0.05+0.1+0.25=0.4

$P(Y=1|X=3)=\frac{P(X=3,Y=1)}{P(X=3)} =\frac{p(3,1)}{P(X=3)}=\frac{0.05}{0.4}= 0.125$

Hence P(Y=1|X=3)=0.125

8 0

2 years ago