Answer: hypotenuse = 
Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (
) of the right triangle, .i.e.:

In this question:
= 
2bc
Substituing and taking square root to find hypotenuse:

Calculating:


=
, then:


Hypotenuse for the right-angled triangle is
units
Answer:
Cylinder Volume = PI * radius^2 * height
Radius = Square Root [Volume / (PI * height)]
Radius = Square Root [ 134 / (3.14 * 7.1)]
Radius = 2.45103
Radius = 2.45
Step-by-step explanation:
Answer:
Step-by-step explanation:
The anwser is 2,3,4,5
Answer:
positive
Step-by-step explanation:
it is positive
The answer is 11 i
<em /><em>Explanation:
</em>
The square root needs to be a number that can be multiplied by itself and equal the original number.
In this case, the number is 11, 11*11 = 121
However, you are looking for the square root of a negative number, due to this you would add i to the answer,
i = imaginary number, or -
( Depending on your grade/ teacher however, you can put "no solution"