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3 years ago

12

On his first day of school, Kareem found the high temperature in degrees Fahrenheit to be 76.1°. He plans to use the function to

convert this temperature from degrees Fahrenheit to degrees Celsius. What does C(76.1) represent

1 answer:

Alexandra [31]3 years ago

3 0

24.5 Celsius.
<span>
</span>The temperature t in degreen Celsius is equal to the temperature T in the degrees Fahrenheit minus 32, times 5/9

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PLZ HELP ANSWER AND EXPLAIN. (photo) #8

evablogger [386]

The picture shown is a unfolded rectangular prism.

The formula to find the surface area of a rectangular prism is:

A = 2(WL+HL+HW)

(W = width, L = Length, H= Height)

So we would need to determine the Height, Length, and Width first, and then plug them into the formula and solve for the area.

In this case:
The height is: 4 cm
The length is: 10.5 cm
The width is: 6.4 cm

Now that we have determined the height, length, and width, we simply plug them into the formula I showed earlier.

In this case the answer would be 269.6.

D. 269.6

8 0

3 years ago

How do you find the surface area of a regular triangular prism

Dmitry [639]

So a triangular prisim is like a triangle stacked on top of x number of identical triangles making a height, like a piece of paper made into a stack

so
basically find the area of each side and add

look at diagram/attachment
find area of triangle
1/2 b times h= area of 1 triangular face

multiply by 2 because 2 sides so 1/2 times 2 b times h=b times h

then 3 other sides
find area of each side and add
areas=(H times B)+(H times c)+(H times a)

so SA=(b times H)+(H times B)+(H times c)+(H times a)

8 0

3 years ago

The graph below shows the height of a kicked soccer ball f(x), in feet, depending on the distance from the kicker x, in feet: Gr

siniylev [52]

Because the vertex of the parabola is at (16,0), its equation is of the formy = a(x-10)² + 15
The graph goes through (0,0), thereforea(0 - 10)² + 15 = 0100a = -15a = -0.15
The equation is y = f(x) = -0.15(x - 10)² + 15
The graph is shown below.
Part A
Note that y = f(x).
The x-intercepts identify values where the function or y=0. The x-intercepts occur at x=0 and x=20, or at (0,0) and (20,0).
The maximum value of y occurs at the vertex (10, 15) because the curve is down due to the negative leading coefficient of -0.15.
The curve increases in the interval x = (-∞, 10) and it decreases in the interval x = (10, ∞).
Part B
When x=12, y = -0.15(12 - 10)² + 15 = 14.4When x=15, y = -0.15(15 - 10)² + 15 = 11.25
The average rate of change between x =12 to x = 15 is(11.25 - 14.4)/(15 - 12) = -1.05
This rate of change represents the slope of the secant line from A to B. It approximates the rate at which f(x) decreases in the interval x =[12, 15].

5 0

3 years ago

Read 2 more answers

What is the expansion of (3+x)^4

Vlad1618 [11]

Answer:

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

Step-by-step explanation:

Considering the expression

$\left(3+x\right)^4$

Lets determine the expansion of the expression

$\left(3+x\right)^4$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=3,\:\:b=x$

$=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i$

Expanding summation

$\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}$

$i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0$

$i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1$

$i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2$

$i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3$

$i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$

as

$\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81$

$\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x$

$\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2$

$\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3$

$\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4$

so equation becomes

$=81+108x+54x^2+12x^3+x^4$

$=x^4+12x^3+54x^2+108x+81$

Therefore,

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

6 0

3 years ago

Karla rode her bicycle 135 miles in 9 weeks, riding the same distance each week. Brad rode his bicycle 102 miles in 6 weeks, rid

blsea [12.9K]

Answer:

Karla's 15 miles per week to Brad's 17 miles per week.

Step-by-step explanation:

First, we would need find the total number of miles each individual rides per week. We do this by dividing the total miles ridden by the number of weeks it took for each individual like so...

Karla: 135 / 9 = 15 miles per week

Brad: 102 / 6 = 17 miles per week

Finally, the comparison would be

Karla's 15 miles per week to Brad's 17 miles per week.

8 0

2 years ago