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Aleks [24]
2 years ago
13

Suppose I have Rs 1000 and I put it in the bank. What will be the amount I have after 5 years if Interest is 5% per annum?​

Mathematics
2 answers:
vichka [17]2 years ago
8 0

Answer:

Its 250 the answer which i got.

Sauron [17]2 years ago
6 0

Answer:

After investing for 5 years at 5% interest, your $1,000 investment will have grown to $1,276

Step-by-step explanation:

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Graph and label the image of the figure below after a dilation by a factor of 1/2.
neonofarm [45]
Answer:

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

see graph below

Explanation:

Given:

The image of a quadrilateral on a coordinate plane

To find:

The coordinates of the new image after dilation of 1/2 have been applied to the original image.

Then graph the coordinates

First, we need to state the coordinates of the original image:

M = (3, -2)

F = (4, -2)

L = (1, -5)

W = (5, -5)

Next, we will apply a scale factor of 1/2:

\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\  \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\  \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\  \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}

The new coordinates:

M' (3/2, -1), F' (2, -1), L' (1/2, -5/2), W' (5/2, -5/2)

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

Plotting the coordinates:

3 0
1 year ago
Eleven subtracted from two times a number is -31.
erica [24]

Answer:

x=-10

Step-by-step explanation:

2x-11=-31\\

Add 11 on both sides.

2x-11=-31\\2x=-20\\2x/2x=-20/2\\x=-10

7 0
2 years ago
Kenny had 5/7 more trading cards than lee. After Kenny collected 50% more trading cards, he had 220 more trading cards than lee.
svp [43]

Answer:

Step-by-step explanation:

Let X is the number of cards Kenny has

Let Y is the number of cards Lee has

1. Kenny had 5/7 more trading cards than lee, it means

X = Y + 5/7X (1)

2. After Kenny collected 50% more trading cards, he had 220 more trading cards than lee, it means:

X + 50%X = Y +  220 (2)

So, we solve the 2 equations to find out X and Y

\left \{ {{X=Y + 5/7X} \atop {1.5X=Y +220}} \right.

<=> X = \frac{3080}{17} and Y = \frac{880}{17}

<=> X ≈181 and Y ≈ 52

6 0
3 years ago
Simplify completely quantity x squared plus 4 x minus 45 all over x squared plus 10 x plus 9 and find the restrictions on the va
Brums [2.3K]

Answer:

A) Quantity x minus 5 over quantity x plus 1, where x≠-1 and x≠-9

Step-by-step explanation:

\frac{x^2 + 4x - 45}{x^2 + 10x + 9}

Simplifying the numerator first:

x² + 4x - 45 using the quadratic formula you get;

(x - 5)(x + 9)

Then simplifying the denominator x² + 10x + 9 using a quadratic formula you get;

(x + 1)(x + 9)

Dividing the numerator and denominator now gives;

\frac{(x - 5)(x + 9)}{(x + 1)(x + 9)}

Cancelling (x + 9) throughout leaves you with;

\frac{x - 5}{x + 1}

The only restrictions here is if x = 1 and 9 which will give an undefined answer.

7 0
4 years ago
Read 2 more answers
What is the value of 5^3¡^9
OLEGan [10]

Answer:

125i

Step-by-step explanation:

We want to find

5^3i^9

This can be rewritten as;

5^3i^8\times i

5^3(i^2)^4\times i

Recall that; i^2=-1

5^3(-1)^4\times i

We evaluate now to obtain;

125(1)\times i=125i

6 0
3 years ago
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