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Katyanochek1 [597]
3 years ago
12

Turn -3/11 into a decimal

Mathematics
2 answers:
777dan777 [17]3 years ago
7 0

-3 ÷ 11

-0.2727 continuing

lutik1710 [3]3 years ago
4 0
-0.272727272727272727272727272727
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Which of these equations share the same solution?<br> A) 4=4 <br> B) 3−=16<br> C) 2+=12<br> D) 2= 2
olga nikolaevna [1]

Answer:

A

Step-by-step explanation:

a and d look similar but I'm quite sure it's a

7 0
2 years ago
The scale of the floor plan of a room is 1 cm : 6.5 m. On the floor plan, the room is 3 cm long by 2 cm wide. What are the actua
elena-s [515]

Answer:

The room is 19,5m long and 13m wide.

Step-by-step explanation:

1cm -> 6,5m

3cm -> 19,5m

2cm -> 13m

3 0
3 years ago
You are given 1000 one dollar bills and 10 envelopes. Put the bills into the envelopes in such a way that someone can ask you fo
taurus [48]

Answer:

We can do it with envelopes with amounts $1,$2,$4,$8,$16,$32,$64,$128,$256 and $489

Step-by-step explanation:

  • Observe that, in binary system, 1023=1111111111. That is, with 10 digits we can express up to number 1023.

This give us the idea to put in each envelope an amount of money equal to the positional value of each digit in the representation of 1023. That is, we will put the bills in envelopes with amounts of money equal to $1,$2,$4,$8,$16,$32,$64,$128,$256 and $512.

However, a little modification must be done, since we do not have $1023, only $1,000. To solve this, the last envelope should have $489 instead of 512.

Observe that:

  1. 1+2+4+8+16+32+64+128+256+489=1000
  2. Since each one of the first 9 envelopes represents a position in a binary system, we can represent every natural number from zero up to 511.
  3. If we want to give an amount "x" which is greater than $511, we can use our $489 envelope. Then we would just need to combine the other 9 to obtain x-489 dollars. Since x-489\leq511, by 2) we know that this would be possible.

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2x%7D%20%2B%2012%20%3D%20x%20%2B%208%20" id="TexFormula1" title=" \sqrt{2x} + 12
Helga [31]
First note that x\ge0; otherwise \sqrt{2x} is undefined as long as we're only looking for real solutions.

We can write

\sqrt{2x}+12=x+8
\sqrt{2x}=x-4
2x=(x-4)^2
2x=x^2-8x+16
x^2-10x+16=0
(x-8)(x-2)=0

\implies x=8,x=2
4 0
3 years ago
100.00=137.76/(1+r)^5<br> solve for r<br><br> thanks much
Feliz [49]
(1+r)^5=137.76/100
1+r=(137.76/100)^(1/5)
R=(137.76/100)^(1/5))-1
5 0
3 years ago
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