Answer:
60 miles; $30
Step-by-step explanation:
Given:
y = 0.25x + 15 ...........Eq1
y = 0.50x.............Eq2
Where, x = miles and y = Total cost of ranting
Find:
Total cost of ranting.
Computation:
From Eq1 and Eq2
0.25x + 15 = 0.50x
0.25x = 15
x = 15 / 0.25
x = 60 miles
From Eq 2
y = 0.50(60)
y = $30
Answer:
1
Step-by-step explanation:
Any number to the 0 power is equal to 1.
Hope that this helps!
The answer is a because a point has no dimensions its just marking a spot <span />
Answer: 0.55567
Step-by-step explanation:
Given : A certain brand of refrigerator has a useful life that is normally distributed with mean 10 years and standard deviation 3 years. The useful lives of these refrigerators are independent.
i.e.
![\mu=10\text{ years}\\\sigma=3\text{ years}](https://tex.z-dn.net/?f=%5Cmu%3D10%5Ctext%7B%20years%7D%5C%5C%5Csigma%3D3%5Ctext%7B%20years%7D)
Let
and
are two randomly selected refrigerator's life whose sum will exceed third selected refrigerator
.
So that, ![X =X_1+X_2-1.9\times X_3](https://tex.z-dn.net/?f=X%20%3DX_1%2BX_2-1.9%5Ctimes%20X_3)
Mean ![=E(X_1)+E(X_2)-E(X_3)=10+10-1.9\times10 =1](https://tex.z-dn.net/?f=%3DE%28X_1%29%2BE%28X_2%29-E%28X_3%29%3D10%2B10-1.9%5Ctimes10%20%3D1)
Standard deviation =![\sqrt{(Var(X_1)+Var(X_1)+Var(X_1))}](https://tex.z-dn.net/?f=%5Csqrt%7B%28Var%28X_1%29%2BVar%28X_1%29%2BVar%28X_1%29%29%7D)
![=\sqrt{(3^2+3^2+(1.9\times3)^2)}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%283%5E2%2B3%5E2%2B%281.9%5Ctimes3%29%5E2%29%7D)
![=7.1056315694](https://tex.z-dn.net/?f=%3D7.1056315694)
Z-score : ![z=\dfrac{X-E[x]}{\sqrt{Var[x]}}=\dfrac{0-1}{7.0156315694}\approx-0.14](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7BX-E%5Bx%5D%7D%7B%5Csqrt%7BVar%5Bx%5D%7D%7D%3D%5Cdfrac%7B0-1%7D%7B7.0156315694%7D%5Capprox-0.14)
Now , The probability that the total useful life of two(i..e n=2) randomly selected refrigerators will exceed 1.9 times the useful life of a third randomly selected refrigerator would be :-
![P(Z>-0.14)=P(Z](https://tex.z-dn.net/?f=P%28Z%3E-0.14%29%3DP%28Z%3C0.14%29%3D0.55567)
Hence, the required probability is 0.55567.
43/100 ... you can't reduce since nothing goes evenly into both the numberator and denominator