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3 years ago

The number 2400 is first increased by 30%.The value obtained is next decreased by 20%.Find the final number

Mathematics

1 answer:

kvasek [131]3 years ago

3 0

2400 is increased by 30%.

so,

2400 + (30/100 * 2400)

2400 + (30 * 24)

2400 + 720

3120

this number is decreased by 20%.

so,

3120 - (20/100 * 3120)

3120 - (2 * 312)

3120 - 624

2496

therefore, the final number will be 2496.

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Simplify the exponential expression. ( 1/5 ) 2 =

Ierofanga [76]

Answer:

Fraction form- 2/5

Decimal form- 0.4

Step-by-step explanation:

Distribute.

Have a good day!

7 0

3 years ago

Read 2 more answers

All the questions please

lesya [120]

I don't mean to sound rude or anything but if you go off of the directions up top then you might be able to find the answer these questions are fairly easy and understandable

3 0

3 years ago

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Plss solve 29 for me.with the steps plsssßs I am begging u

lakkis [162]

That means that the first rectangle and the first triangle ave athe same perimiter

so therefor
perimiter=sides added up
rectangle has 4 sides bu 2 is given so double it since the other side is same legnth
rec=x+x+4
multiply 2
2x+2x+8=4x+8=perimiter
this is equal to perimiter of triangle which is
x+9+x+5+x=3x+14
therefor
4x+8=3x+14
subtract 3x from both sides
x+8=14
subtract 8 from both sides
x=6
first one x=6

second rectangle and second triangle
s+7 and 3s
2 sides
2s+14+6s=p
8s+14=p

traignel=2s+12+2s+12+2s+12=6s+36=p
they are equal so
8s+14=6s+36
subtract 6s from both sides
2s+14=36
subtract 14 from both sides
2s=22
divide both sideds by 2
s=11

the values are
pair one:
x=6

pair 2:
s=11

5 0

3 years ago

2(5 + 9) – 6 plz help me i need it in 2 minuts

pishuonlain [190]

Answer:

2(5+9)_6

=10+18_6

=22

is it wht u require

7 0

3 years ago

Consider the implicit differential equation <img src="https://tex.z-dn.net/?f=%2849%20y%5E%7B3%7D%20%2B%2045%20xy%29%20dx%20%2B%

BaLLatris [955]

We're looking for an integrating factor $\mu(x,y)=x^py^q$ such that

$\mu\underbrace{(49y^3+45xy)}_M\,\mathrm dx+\mu\underbrace{(98xy^2+50x^2)}_N\,\mathrm dy=0$

is exact, which would require that

$(\mu M)_y=(\mu N)_x$
$(49x^py^{q+3}+45x^{p+1}y^{q+1})_y=(98x^{p+1}y^{q+2}+50x^{p+2}y^q)_x$
$49(q+3)x^py^{q+2}+45(q+1)x^{p+1}y^q=98(p+1)x^py^{q+2}+50(p+2)x^{p+1}y^q$
$\implies\begin{cases}49(q+3)=98(p+1)\\45(q+1)=50(p+2)\end{cases}\implies p=\dfrac52,q=4$

You can verify that $(\mu M)_y=(\mu N)_x$ if you'd like. With the ODE now exact, we have a solution $F(x,y)=C$ such that

$F_x=\mu M$
$F=\displaystyle\int(49y^3+45xy)x^{5/2}y^4\,\mathrm dx$
$F=10x^{9/2}y^5+14x^{7/2}y^7+f(y)$

$F_y=\mu N$
$50x^{9/2}y^4+98x^{7/2}y^6+f'(y)=98x^{7/2}y^2+50x^{9/2}y^4$
$f'(y)=0$
$\implies f(y)=C$

and so the general solution is

$F(x,y)=10x^{9/2}y^5+14x^{7/2}y^7=C$

8 0

3 years ago