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weeeeeb [17]
3 years ago
11

The number 2400 is first increased by 30%.The value obtained is next decreased by 20%.Find the final number

Mathematics
1 answer:
kvasek [131]3 years ago
3 0

<em>2400 is increased by 30%.</em>

so,

2400 + (30/100 * 2400)

2400 + (30 * 24)

2400 + 720

3120

<em>this number is decreased by 20%.</em>

so,

3120 - (20/100 * 3120)

3120 - (2 * 312)

3120 - 624

2496

therefore, the final number will be 2496.

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Simplify the exponential expression. ( 1/5 ) 2 =
Ierofanga [76]

Answer:

Fraction form- 2/5

Decimal form- 0.4

Step-by-step explanation:

Distribute.

Have a good day!

7 0
3 years ago
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All the questions please
lesya [120]
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3 years ago
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Plss solve 29 for me.with the steps<br> plsssßs I am begging u
lakkis [162]
That means that the first rectangle and the first triangle ave athe same perimiter

so therefor
perimiter=sides added up
 rectangle has 4 sides bu 2 is given so double it since the other side is same legnth
rec=x+x+4
multiply 2
2x+2x+8=4x+8=perimiter
this is equal to perimiter of triangle which is
x+9+x+5+x=3x+14
therefor
4x+8=3x+14
subtract 3x from both sides
x+8=14
subtract 8 from both sides
x=6
first one x=6





second rectangle and second triangle
s+7 and 3s
2 sides
2s+14+6s=p
8s+14=p

traignel=2s+12+2s+12+2s+12=6s+36=p
they are equal so
8s+14=6s+36
subtract 6s from both sides
2s+14=36
subtract 14 from both sides
2s=22
divide both sideds by 2
s=11






the values are
pair one:
x=6

pair 2:
s=11

5 0
3 years ago
2(5 + 9) – 6 plz help me i need it in 2 minuts
pishuonlain [190]

Answer:

2(5+9)_6

=10+18_6

=22

is it wht u require

7 0
3 years ago
Consider the implicit differential equation <img src="https://tex.z-dn.net/?f=%2849%20y%5E%7B3%7D%20%2B%2045%20xy%29%20dx%20%2B%
BaLLatris [955]
We're looking for an integrating factor \mu(x,y)=x^py^q such that

\mu\underbrace{(49y^3+45xy)}_M\,\mathrm dx+\mu\underbrace{(98xy^2+50x^2)}_N\,\mathrm dy=0

is exact, which would require that

(\mu M)_y=(\mu N)_x
(49x^py^{q+3}+45x^{p+1}y^{q+1})_y=(98x^{p+1}y^{q+2}+50x^{p+2}y^q)_x
49(q+3)x^py^{q+2}+45(q+1)x^{p+1}y^q=98(p+1)x^py^{q+2}+50(p+2)x^{p+1}y^q
\implies\begin{cases}49(q+3)=98(p+1)\\45(q+1)=50(p+2)\end{cases}\implies p=\dfrac52,q=4

You can verify that (\mu M)_y=(\mu N)_x if you'd like. With the ODE now exact, we have a solution F(x,y)=C such that

F_x=\mu M
F=\displaystyle\int(49y^3+45xy)x^{5/2}y^4\,\mathrm dx
F=10x^{9/2}y^5+14x^{7/2}y^7+f(y)

F_y=\mu N
50x^{9/2}y^4+98x^{7/2}y^6+f'(y)=98x^{7/2}y^2+50x^{9/2}y^4
f'(y)=0
\implies f(y)=C

and so the general solution is

F(x,y)=10x^{9/2}y^5+14x^{7/2}y^7=C
8 0
3 years ago
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