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scZoUnD [109]
3 years ago
11

Brenda does household chores for neighbors to earn spending money. One week she worked 312 hours for $4.75 an hour, 6 hours and

20 minutes for $5.75 an hour, and 834 hours for $3.25 an hour. To the nearest 10 dollars, how much did she make that week?
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
8 0

Answer:76

Step-by-step explanation:

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It takes Santa 2 minutes to deliver presents to 5 houses. At this rate, how long will it take him to deliver to a neighborhood o
dolphi86 [110]

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28

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6 0
3 years ago
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Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 250 feet and a s
Korvikt [17]

Answer:

On the graphing calculator, use the function normCdf, where

  • lower bound = -9999
  • upper bound = 210
  • mean = 250
  • standard deviation = 46

It will result in normCdf(-9999,210,250,46) ≈ 0.192269 or 19.2269%

6 0
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Every female bear has 3 baby cubs. What is the constant of proportionality for the ratio of cubs to female bears? (4 points)
andrezito [222]

Answer:

3:1 ratio

Step-by-step explanation:

5 0
3 years ago
What’s the answer to the math problem? (3x+2)(2x2+x+3
sergey [27]

{6x}^{3}  +  {7x}^{2}  + 11x + 6
factor out the function
8 0
3 years ago
Use the given transformation to evaluate the given integral, where r is the triangular region with vertices (0, 0), (8, 1), and
Jlenok [28]
We first obtain the equation of the lines bounding R.

For the line with points (0, 0) and (8, 1), the equation is given by:

\frac{y}{x} = \frac{1}{8}  \\  \\ \Rightarrow x=8y \\  \\ \Rightarrow8u+v=8(u+8v)=8u+64v \\  \\ \Rightarrow v=0

For the line with points (0, 0) and (1, 8), the equation is given by:

\frac{y}{x} = \frac{8}{1}  \\  \\ \Rightarrow y=8x \\  \\ \Rightarrow u+8v=8(8u+v)=64u+8v \\  \\ \Rightarrow u=0

For the line with points (8, 1) and (1, 8), the equation is given by:

\frac{y-1}{x-8} = \frac{8-1}{1-8} = \frac{7}{-7} =-1 \\  \\ \Rightarrow y-1=-x+8 \\  \\ \Rightarrow y=-x+9 \\  \\ \Rightarrow u+8v=-8u-v+9 \\  \\ \Rightarrow u=1-v

The Jacobian determinant is given by

\left|\begin{array}{cc} \frac{\partial x}{\partial u} &\frac{\partial x}{\partial v}\\\frac{\partial y}{\partial u}&\frac{\partial y}{\partial v}\end{array}\right| = \left|\begin{array}{cc} 8 &1\\1&8\end{array}\right| \\  \\ =64-1=63

The integrand x - 3y is transformed as 8u + v - 3(u + 8v) = 8u + v - 3u - 24v = 5u - 23v

Therefore, the integration is given by:

63 \int\limits^1_0 \int\limits^{1}_0 {(5u-23v)} \, dudv =63 \int\limits^1_0\left[\frac{5}{2}u^2-23uv\right]^{1}_0 \\  \\ =63\int\limits^1_0(\frac{5}{2}-23v)dv=63\left[\frac{5}{2}v-\frac{23}{2}v^2\right]^1_0=63\left(\frac{5}{2}-\frac{23}{2}\right) \\  \\ =63(-9)=|-576|=576
6 0
3 years ago
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