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pishuonlain [190]
3 years ago
6

How to do this Question a please help from the smallest to the biggest

Mathematics
2 answers:
IrinaK [193]3 years ago
7 0
To solve this type of problems, the easiest way to compare is to change them all to fractions, or to decimals, whichever is easier for you.

For the first one, change them all to decimals,
A. 525/1000=0.525
B. 3/4 = 0.750
C. 0.55 =0.550
Thus it will be obvious, whether you'd like smallest to biggest or otherwise.

For the second problem, 
A. 3.85=3.850
B. 3 5/8 = 3.625
C. 3.805 = 3.850

Choose the smallest to biggest.



Pachacha [2.7K]3 years ago
5 0
A. turn all fractions into decimals or all decimals into fractions; I've decided to turn all fractions into decimals

525
------- = 0.525
1000

3
-- = 0.75 = 0.750 ~ (add a zero at the end to make the decimal places         4                                equal with 0.525)

0.55 = 0.55 = 0.550 ~<span>(add a zero at the end to make the decimal places                                         equal with 0.525 and 0.750)
</span>
<span>                                          Answer to Problem 'a':</span>

Smallest = 0.525 = 525
                              -------
                              1000

Middle = 0.550 = 0.55

Largest = 0.750 = 3
                              --
                              4

b. <span>turn all fractions/mixed fractions into decimals or all decimals into fractions; I've decided to turn all fractions/mixed fractions into decimals
</span>
3.805 = 3.805

3.85 = 3.850 ~ ( <span>add a zero at the end to make the decimal places equal                                with 3.805)
</span>
3 4/5 = 80
           ----- = 0.80  =0.800 ~ (add a zero at the end to make the decimal
           100                              places equal with 3.805 and 3.850)

                                 Answers to Problem 'b':

Smallest = 0.800 = 0.80 = 3 4/5

Middle = 3.805 = 3.805

Largest = 3.850 = 3.85

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Write 5.641 in word form
WINSTONCH [101]

Answer:

Five and Six hundred Forty one thousandths

Step-by-step explanation:

5.641 in words can be written as

the first number is considered same, decimal is considered as and and digits after decimal are considered as regular number.

So, 5.641 in word form is:

Five and Six hundred Forty one thousandths

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3 years ago
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15. A rectangle has a length of 2x - 1 and a width of 3x + 7. Find the perimeter of this rectangle.
andrew11 [14]

Answer:

10x + 12 and 6x² + 11x - 7

Step-by-step explanation:

The perimeter (P) of a rectangle is calculated as

P = 2l + 2w ( l is length and w is width )

   = 2(2x - 1) + 2(3x + 7) ← distribute parenthesis

    = 4x - 2 + 6x + 14 ← collect like terms

     = 10x + 12

--------------------------------------------------

The area (A) of a rectangle is calculated as

A = lw

   = (2x - 1)(3x + 7) ← expand using FOIL

    = 6x² + 14x - 3x - 7 ← collect like terms

    = 6x² + 11x - 7

7 0
3 years ago
The weight of a child in 1990 was 40 lb. By 2005, the child's weight
Maslowich

Answer:

225%

Step-by-step explanation:

1. Divide the new weight by the original weight.

90/40 = 2.25.

2. Multiply by 100 to get the percentage.

2.25 x 100 = 225%

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3 years ago
??????????????????????????????????​
iogann1982 [59]

Answer:

angle 3 is 140°

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​write the logarithm as a sum or difference of logarithms. simplify each term as much as possible. log4(6ab)
Dominik [7]

The logarithm written as a sum of logarithm and simplified as much as possible is \frac{1}{2} +log_{4 }3 +  log_{4 }a + log_{4 }b

<h3>Simplifying Logarithms</h3>

From the question, we are to write the given logarithm expression as a sum or difference of logarithms

The given logarithm is

log_{4 }6ab

This can be written as

log_{4 }6 \times a \times b

From one of the rules of logarithm, we have that

log_{x }yz= log_{x }y + log_{x }z

Thus,

log_{4 }6 \times a \times b  becomes

log_{4 }6 + log_{4 }a + log_{4 }b

This can be further simplified into

log_{4 }3 \times 2 + log_{4 }a + log_{4 }b

log_{4 }3 + log_{4 }2 + log_{4 }a + log_{4 }b

If desired, this can be further simplified into

log_{4 }3 + log_{2^{2}  }2 + log_{4 }a + log_{4 }b

log_{4 }3 + \frac{1}{2} log_{2}2 + log_{4 }a + log_{4 }b

log_{4 }3 + \frac{1}{2} (1)+ log_{4 }a + log_{4 }b

\frac{1}{2} +log_{4 }3 +  log_{4 }a + log_{4 }b

Hence, the logarithm written as a sum of logarithm and simplified as much as possible is \frac{1}{2} +log_{4 }3 +  log_{4 }a + log_{4 }b

Learn more on Simplifying logarithms here: brainly.com/question/17851187

#SPJ1

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