Question

A certain lottery has 38 numbers. In how many different ways can 4 of the numbers be​ selected? (Assume that order of selection is not​ important.)

Answer 1

Answer:

There are 73815 ways of selecting 4 of the lottery numbers.

Step-by-step explanation:

The total amount of ways to pick 4 numbers from a set of 38 ignoring the order is given by the combinatorial number of 38 with 4, denoted by ${38 \choose 4}$ , which is

${38 \choose 4} = \frac{38!}{4!(38-4)!} = 73815$

Therefore, there are 73815 ways of picking 4 of the numbers.

Answer 2

Answer:

We conclude that have 73815 a different ways.

Step-by-step explanation:

We know that a certain lottery has 38 numbers. We assume that order of selection is not​ important. We calculate  how many different ways can 4 of the numbers be​ selected.

So out of 38 numbers we choose 4 numbers. We get:

$C_4^{38}=\frac{38!}{4!(38-4)!}=73815$

We conclude that have 73815 a different ways.