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Verdich [7]
3 years ago
10

A box of crackers has 24 grams of fat.The box contains 8 servings.Whats the unit rate?

Mathematics
1 answer:
ankoles [38]3 years ago
4 0
The answer is D. It is that because there are a total 24 grammes of fat and a total of 8 servings. To get your answer you have to divide 24 by 8 (24/8)=3 
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Rhonda drove 51 miles per hour for 5 hours. She then drove 55 miles per hour for x hours. Which expression is equivalent to the
lawyer [7]

The expression equivalent to the total distance Rhonda drove is 51x = 275

Given:

Distance 1:

Number of miles = 51 miles

Number of hours = 5 hours

Distance 2:

Number of miles = 55 miles

Number of hours = x hours

<em>Ratio of miles to number of hours</em> = 51 miles : 5 hours

<em>Ratio of miles to number of hours</em> = 55 miles : x hours

Equate the ratios

51 : 5 = 55 : x

51/5 = 55/x

cross product

51 × x = 5 × 55

51x = 275

x = 275 / 51

x = 5.392156862745098

Approximately,

x = 5.4 hours

Therefore, the number of hours taken to travel 55 miles is 5.4 hours

Read more:

brainly.com/question/3796978

7 0
2 years ago
Please help with this thank youu
Arte-miy333 [17]

Answer:

D = 106

e = 54

f = 20

Step-by-step explanation:

its ur answer

6 0
3 years ago
Read 2 more answers
Which data set is represented by the modified box plot? 45,50,55,60,65,70,75,80,85,90,95,100,105,110,115
stellarik [79]
120,125,130,135,140,145,150,155,160,165,170,175,180,185
7 0
3 years ago
Solve for x.<br><br> -3x+x=2(x-3)
Nat2105 [25]

Answer:

x=-\frac{3}{2}

Step-by-step explanation:

-3x+x=2(x-3)\\ \Leftrightarrow -2x=2x-6\\ \Leftrightarrow 4x=-6\\ \Leftrightarrow x=-\frac{3}{2}

5 0
3 years ago
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Assume that a sample is used to estimate a population proportion μ . Find the margin of error M.E. that corresponds to a sample
hichkok12 [17]

Answer:

MoE = 1.645\cdot \frac{13.1}{\sqrt{772} } \\\\MoE = 1.645\cdot 0.47147\\\\MoE = 0.776\\\\

Step-by-step explanation:

Since the sample size is quite large, we can use the z-distribution.

The margin of error is  given by

$ MoE = z_{\alpha/2}(\frac{s}{\sqrt{n} } ) $

Where n is the sample size, s is the sample standard deviation and z_{\alpha/2} is the z-score corresponding to a 90% confidence level.

The z-score corresponding to a 90% confidence level is

Significance level = α = 1 - 0.90= 0.10/2 = 0.05

From the z-table at α = 0.05

z-score = 1.645

MoE = 1.645\cdot \frac{13.1}{\sqrt{772} } \\\\MoE = 1.645\cdot 0.47147\\\\MoE = 0.776\\\\

Therefore, the margin of error is 0.776.

3 0
2 years ago
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