There are different ways to solve a quadratic equation, the main ones that i'm thinking about right now are:
1) factor the equation as a product:
ex: x^2+ 4x + 3 =0
(x+3) (x+1) = 0
x=-3 and x=-1 are the solutions.
To find (x+p) and (x+q) you have to think that (p+q )have to be equal to the number that is multiplied by x, in my example it was 4 (3+1=4), (p times q) have to be equal to the last number of the quadratic equation, the one that is not multiplied by any x, that in my example is 3 (3 x 1= 3)
2) The other way to solve a quadratic function is by using a formula:
given: ax^2 +bx +c=0
x= (-b +/- <span>√(b^2 -</span> 4ac)) / 2a
ex: 3x^2 + 4x -2=0
x= (-4 +/- √16-4(3)(-2)) / 6= (-4 +/- √16+24)/6= (-4 +/- <span>√40) / 6
now there are 2 possibilities: x= (-4+</span><span>√40) /6
and
x= (-4 - </span><span>√40) / 6
I hope the examples were clear enough also if i did't get very nice numbers. Look closely to the sings + and -, they are very important</span>
Answer:
ok so this problem you are basically just rearranging it. you're going to want y by itself.
Step-by-step explanation:
let's start with the original equation: 5-y=1/3x +12
so first you have to move the five over, so you subtract 5 from both sides. -y=1/3x+12-5
then you subtract the 5 from the twelve since they're like terms: -y=1/3x+7
and finally you have to move the negative over. when you move the negative think of it like dividing negative one from both sides, everything on the other side has to get the negative.
so we're left with y=-1/3x-7
I hope this helps!
10 pounds of sugar for 5 litres of cream.
Let "what" and "what" be A and B
Put this in an algebraic equation
A * B = 21
A + B = -22
A must = -21 and B must = -1 , this is because two negatives multiply to make a positive
A + B = -22 , -21 +-1 = -22
Answer:
........??
Step-by-step explanation:
huh whattt
