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Len [333]
3 years ago
12

Prove whether the following inferences are valid using the long or short truth table method. If they are invalid, give the count

erexample.
A > -B |= B > -A​
Mathematics
1 answer:
bezimeni [28]3 years ago
7 0

Answer:

6

Step-by-step explanation:

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Find the vertex of the parabola given by the following equation y=x2+10x+33
vovikov84 [41]
\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\

\begin{array}{llccll}
y = &{{ 1}}x^2&{{ +10}}x&{{ +33}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
6 0
4 years ago
A college has an acceptance rate of 17%. If 3,240 students apply, about
zloy xaker [14]

Answer:

550

Step-by-step explanation:

so we know that 17% of everyone who applies (3,240) will be accepted.

0.17*3,240= 550.8

550 students will be accepted

we have to round down as only 17% can be accepted and u cant have 0.8th of a person

hope this helps

6 0
4 years ago
4(2x + 1) = 2(x - 13)
MakcuM [25]
The answer would be -5.
4 0
3 years ago
There is a line through the origin that divides the region bounded by the parabola y=2x-4x^2 and the x-axis into two regions wit
shtirl [24]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

y = 7x - 4x² 

<span>7x - 4x² = 0 </span>

<span>x(7 - 4x) = 0 </span>

<span>x = 0, 7/4 </span>

<span>Find the area of the bounded region... </span>

<span>A = ∫ 7x - 4x² dx |(0 to 7/4) </span>

<span>A = 7/2 x² - 4/3 x³ |(0 to 7/4) </span>

<span>A = 7/2(7/4)² - 4/3(7/4)³ - 0 = 3.573 </span>

<span>Half of this area is 1.786, now set up an integral that is equal to this area but bounded by the parabola and the line going through the origin... </span>

<span>y = mx + c </span>

<span>c = 0 since it goes through the origin </span>

<span>The point where the line intersects the parabola we shall call (a, b) </span>

<span>y = mx ===> b = m(a) </span>

<span>Slope = m = b/a </span>

<span>Now we need to integrate from 0 to a to find the area bounded by the parabola and the line... </span>

<span>1.786 = ∫ 7x - 4x² - (b/a)x dx |(0 to a) </span>

<span>1.786 = (7/2)x² - (4/3)x³ - (b/2a)x² |(0 to a) </span>

<span>1.786 = (7/2)a² - (4/3)a³ - (b/2a)a² - 0 </span>

<span>1.786 = (7/2)a² - (4/3)a³ - b(a/2) </span>

<span>Remember that (a, b) is also a point on the parabola so y = 7x - 4x² ==> b = 7a - 4a² </span>
<span>Substitute... </span>

<span>1.786 = (7/2)a² - (4/3)a³ - (7a - 4a²)(a/2) </span>

<span>1.786 = (7/2)a² - (4/3)a³ - (7/2)a² + 2a³ </span>

<span>(2/3)a³ = 1.786 </span>

<span>a = ∛[(3/2)(1.786)] </span>

<span>a = 1.39 </span>

<span>b = 7(1.39) - 4(1.39)² = 2.00 </span>

<span>Slope = m = b/a = 2.00 / 1.39 = 1.44</span>

7 0
3 years ago
A machining company needs to manufacture more than 20 fixtures in a day. The company uses five identical machines to make the fi
nikklg [1K]

Answer:

A. 5x>20

Step-by-step explanation:

Because the company has to produce more than 20 fixtures you need  greater than 20 and you have 5 machines time the number they produce.

Hope this helps, if it does please mark brainliest!!

3 0
3 years ago
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